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PROCESS FOR THE PREPARATION OF COPPER(II) CHLORIDE FROM COPPER(II) OXYCHLORIDE USING TERTIARY AMINE HYDROCHLORIDES
PROCESS FOR THE PREPARATION OF COPPER(II) CHLORIDE FROM COPPER(II) OXYCHLORIDE USING TERTIARY AMINE HYDROCHLORIDES
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机译:用叔胺盐酸盐从氯化铜(II)制备氯化铜(II)的方法
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摘要
Copper(II) chloride is prepared from copper(II) oxychloride in a nonpolar solvent, preferably during oxychlorination. As the source of hydrogen chloride, the hydrochlorides of certain tertiary amines having 12-40 carbon atoms in total are utilized. The amine contains at most one N-methyl group and its dissociation constant Ka of the equilibrium reaction NR3H(+)+H2O--NR3+H3O(+) is 10-3.5 to 10-8.5. Preferred tertiary amines are a trialkylamine of 15-36 carbon atoms; an N-alkylazacycloalkane of the formula IMAGE wherein R is alkyl of 6-15 carbon atoms, 5/=n/=8, ALK represents one or more alkyl substituents, and the N-alkylazacycloalkane contains at least 15 carbon atoms; or an N,N-dialkylaniline wherein each alkyl group independently contains 6-12 carbon atoms and the benzene ring is optionally substituted by one or more alkyl groups of 1-3 carbon atoms each.
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机译:氯化铜(II)是在非极性溶剂中,优选在氧氯化过程中,由氯氧化铜(II)制备的。作为氯化氢的来源,使用某些总共具有12-40个碳原子的叔胺的盐酸盐。胺含有至多一个N-甲基,并且平衡反应NR3H(+)+ H2O->-NR3 + H3O(+)的解离常数Ka为10-3.5至10-8.5。优选的叔胺是具有15-36个碳原子的三烷基胺;优选的是叔胺。式的N-烷基氮杂环烷烃,其中R是6-15个碳原子的烷基,5 = n = 8,ALK代表一个或多个烷基取代基,并且N-烷基氮杂环烷烃含有至少15个碳原子;或N,N-二烷基苯胺,其中每个烷基独立地含有6-12个碳原子,并且苯环任选地被一个或多个各自具有1-3个碳原子的烷基取代。
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