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SYNTHESIS OF ZEOLITE ZSM-22 WITH A HETEROCYCLIC ORGANIC COMPOUND
SYNTHESIS OF ZEOLITE ZSM-22 WITH A HETEROCYCLIC ORGANIC COMPOUND
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机译:用杂环有机化合物合成ZSM-22分子筛
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摘要
The process for preparing ZSM-22 zeolite comprises preparing a reaction mixture containing water and sources of an alkali metal or alkaline earth metal cation, alumina, silica, and a particular organic promoter, and maintaining the reaction mixture at crystallization conditions until crystals of the ZSM-22 zeolite are formed. …??Such a reaction mixture has the following composition, in terms of mole ratios of oxides:… SiO2/Al2O3 = 20 to INFINITY … H2O/SiO2 = 10 to 100… OH-/SiO2 = 0 to 1.0… M+/SiO2 = 0 to 2.0… RN/SiO2 = 0.01 to 2.0… wherein M+ is alkali metal or alkaline earth metal cation and RN is the functional group of the organic promoter. The organic promoter is a heterocyclic organic compound containing one or more four (4) to ten (10) member, saturated or unsaturated, non-fused rings, wherein the hetero atoms are the same or different and can be oxygen, phosphorous or nitrogen, an alkyl and/or alkene derivative of such heterocyclic organic compounds, wherein the alkyl and/or alkene groups contain one (1) to ten (10) carbon atoms, or an organic or inorganic salt of or cation derived from the heterocyclic organic compound or its alkyl or alkene derivative. The zeolite ZSM-22 as synthesized from such a reaction mixture is also claimed.
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机译:制备ZSM-22沸石的方法包括制备包含水和碱金属或碱土金属阳离子,氧化铝,二氧化硅和特定的有机促进剂源的反应混合物,并将反应混合物保持在结晶条件下直至ZSM晶体结晶。形成-22沸石。 ……以氧化物的摩尔比计,这样的反应混合物具有以下组成:…SiO 2 / Al 2 O 3 = 20至无穷大…H 2 O / SiO 2 = 10至100…OH-/ SiO 2 = 0至1.0… M + / SiO 2 = 0至2.0…RN / SiO 2 = 0.01至2.0…其中M +是碱金属或碱土金属阳离子,并且RN是有机促进剂的官能团。有机促进剂是含有一个或多个四(4)至十(10)个饱和或不饱和非稠合环的杂环有机化合物,其中杂原子相同或不同,可以是氧,磷或氮,此类杂环有机化合物的烷基和/或烯烃衍生物,其中烷基和/或烯烃基团包含一个(1)至十(10)个碳原子,或衍生自该杂环有机化合物的有机或无机盐或阳离子或其烷基或烯烃衍生物。还要求保护由这种反应混合物合成的ZSM-22沸石。
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