首页> 外国专利> A METHOD FOR DETERMINING THE THERMAL CONDUCTIVITY OF ANISOTROPIC PLASTIC FILMS AND ITS USAGE

A METHOD FOR DETERMINING THE THERMAL CONDUCTIVITY OF ANISOTROPIC PLASTIC FILMS AND ITS USAGE

机译:一种确定各向异性塑料薄膜热导率的方法及其用途

摘要

The invention relates to a method for determining the thermal conductivity of anisotropic plastic films. A focused and modulated heating beam (11) is directed to a plastic film sample (10), whereby a thermal profile (13) is obtained for the plastic film sample (10) and a medium surrounding it. The thermal profile (13) is inspected by means of a measuring beam (12), whereby a phase and magnitude information (Ζn, Ζt) is obtained for the thermal profile (13) as a function of a transversal offset (14) both for vertical and horizontal deviations. The vertical and horizontal deviation signals of the phase and magnitude information (Ζn, Ζt) are analyzed by means of a projection method, such as a method of partial least squares regression PLS, whereby said thermic wave represents in the analysis a certain matrix (X) and the thermic diffusivity (α) of the plastic film sample (10) is contained as one factor in another matrix (Y). By using known samples or a simulated training set, a PLS model (predictive model) is formed, by means of which the thermic diffusivity (α) of unknown plastic film samples and the thermal conductivity (K) on the basis of the formulas (1): α = K / (ςC) and (2): K = α . ςC are determined.
机译:本发明涉及一种用于确定各向异性塑料膜的导热率的方法。将聚焦和调制的加热束(11)对准塑料膜样品(10),从而获得塑料膜样品(10)和围绕它的介质的热分布(13)。借助于测量光束(12)检查热分布(13),由此获得热分布(13)的,作为横向偏移(14)的函数的相位和大小信息(Zn,Zt)。垂直和水平偏差。通过投影方法,例如偏最小二乘回归PLS方法,分析相位和幅度信息(Zn,Zt)的垂直和水平偏差信号,其中所述热波在分析中表示特定矩阵(X ),而塑料膜样品(10)的热扩散率(α)作为一个因素包含在另一基质(Y)中。通过使用已知的样本或模拟的训练集,形成PLS模型(预测模型),借助该模型,未知塑料薄膜样本的热扩散率(α)和基于公式(1)的热导率(K) ):α= K /(ςC)和(2):K =α。确定ςC。

著录项

相似文献

  • 专利
  • 外文文献
  • 中文文献
获取专利

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号