首页> 外国专利> METHOD FOR SEPARATING DETERMINING QUADRIVALENT SELENIUM FROM HEXAVALENT SELENIUM IN SOLUTION

METHOD FOR SEPARATING DETERMINING QUADRIVALENT SELENIUM FROM HEXAVALENT SELENIUM IN SOLUTION

机译:从溶液中的六价硒分离测定四价硒的方法

摘要

PROBLEM TO BE SOLVED: To obtain a correct measurement value from a stable measurement result in a simple operation even when a content of Se6+ is minute to a content of S4+, by adding hydrochloric acid and nitric acid to a solution in which Se4+ and Se6+ are dissolved, heating and reducing the Se6+ to Se4+. ;SOLUTION: Se4+, Se6+ present in a solution are totally reduced to Se4+ and a total quantity of Se4+ in the solution is measured. A quantity of Se6+ is calculated from a difference of the measured total quantity of Se4+ and a quantity of Se4+ measured without a reduction process. In the reduction process, hydrochloric acid is added as a reducing agent to the solution containing the Se4+ and Se6+ and heated, whereby the solution is reduced to Se4+ and Se6+. At this time, since the Se4+ is reduced far to Se6+ to make determination difficult if a reduction process condition is too intensive, nitric acid having a reduction restriction effect is added thereby restricting a reduction reaction. An addition amount is approximately 35% hydrochloric acid and 61% nitric acid of the sample solution. Too little hydrochloric acid prevents the reduction from proceeding and too much hydrochloric acid forms Se0. Also too little nitric acid forms Se0 thereby lowering a recovery, while too much nitric acid hinders formation of hydride at an analysis time.;COPYRIGHT: (C)1999,JPO
机译:解决的问题:即使在Se 6 + 的含量为S 4 + ,通过向溶解有Se 4 + 和Se 6 + 的溶液中加入盐酸和硝酸,加热并还原Se 6 + 到Se 4 + 。 ;解决方案:溶液中存在的Se 4 + ,Se 6 + 全部还原为Se 4 + 和Se 4 + 。根据测量的Se 4 + 总量与未测量的Se 4 + 量之差计算Se 6 + 量还原过程。在还原过程中,将盐酸作为还原剂添加到含有Se 4 + 和Se 6 + 的溶液中并加热,从而将溶液还原为Se < Sup> 4 + 和Se 6 + 。此时,由于Se 4 + 被还原成Se 6 + ,如果还原工艺条件太强,则难以确定,因此硝酸具有还原限制作用添加α,从而限制还原反应。加入量为样品溶液的约35%盐酸和61%硝酸。盐酸太少会阻止还原的进行,而太多的盐酸会形成Se 0 。硝酸中过少的硝酸也会形成Se 0 ,从而降低回收率,而硝酸中过多的硝酸会阻碍分析时氢化物的形成。;版权所有:(C)1999,JPO

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