首页> 外国专利> DYNAMIC QUANTITY SENSOR AND DISPLACEMENT MEASURING APPARATUS USING THIS DYNAMIC QUANTITY SENSOR, DISPLACEMENT MEASURING METHOD, APPARATUS AND METHOD FOR VIBRATION CONTROL

DYNAMIC QUANTITY SENSOR AND DISPLACEMENT MEASURING APPARATUS USING THIS DYNAMIC QUANTITY SENSOR, DISPLACEMENT MEASURING METHOD, APPARATUS AND METHOD FOR VIBRATION CONTROL

机译:使用该动态量传感器的动态量传感器和位移测量装置,位移测量方法,装置和振动控制方法

摘要

PROBLEM TO BE SOLVED: To directly detect the time differentiation of acceleration, i.e., jerk. ;SOLUTION: If an acceleration (a) acts on a base portion 3, a cantilever body 4 is curved, and an angular velocity Ω is generated at its tip part. The angular velocity Ω is detected by a vibrating gyro 5. If the acceleration (a) is constant, the cantilever body 4 becomes at a standstill at a certain quantity of deflection. Since any angular velocity Ω is not generated at the tip part of the cantilever body 4, on this occasion, the output of the vibrating gyro 5 becomes zero. Until the acceleration (a) changes in point of time, the cantilever body 4 does not curve, and any angular velocity Ω is not generated at the tip part, and the vibrating gyro 5 does not generate an output. Namely, the vibrating gyro 5 outputs a signal according to the time differentiation of the acceleration (a), i.e., jerk.;COPYRIGHT: (C)2001,JPO
机译:要解决的问题:直接检测加速度的时间差异,即加速度。 ;解决方案:如果加速度(a)作用在基部3上,则悬臂梁4弯曲,角速度ω在其尖端部分生成。角速度ω通过振动的陀螺仪5来检测“α”。如果加速度(a)是恒定的,则悬臂体4以一定的偏转量停止。由于任何角速度ω此时,在悬臂体4的前端部不产生“α”,因此,陀螺仪5的输出为零。直到加速度(a)在时间点上变化,悬臂体4才弯曲,并且角速度ω为ω。在前端部不会产生“振动”,振动陀螺仪5也不会产生输出。即,振动陀螺仪5根据加速度(a)的时间微分,即加加速度,输出信号。COPYRIGHT:(C)2001,JPO

著录项

  • 公开/公告号JP2001033477A

    专利类型

  • 公开/公告日2001-02-09

    原文格式PDF

  • 申请/专利权人 LIFE TEC KENKYUSHO:KK;

    申请/专利号JP19990211371

  • 发明设计人 YAMAMOTO SHIZUO;

    申请日1999-07-26

  • 分类号G01P15/00;G01B21/00;G01C19/00;G01H1/00;G01H11/08;G01P9/04;G05D19/00;

  • 国家 JP

  • 入库时间 2022-08-22 01:27:39

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