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METHOD FOR FORMING BOND BETWEEN PLASTIC MATERIAL FOR MAKING FLUID PERCOLATE AND FILTER MATERIAL FOR MAKING FLUID PERCOLATE

机译:用于制造流体渗滤的塑料与用于过滤流体渗滤的过滤材料之间形成粘结的方法

摘要

PROBLEM TO BE SOLVED: To produce a rational filter in comparison with conventional methods. SOLUTION: In the first step, a plastic material is plastified over a part of its depth by a heat source installed at a short distance from a plastification area, in the second step, the heat source is removed, in the third step, the end fringe part of a filter material is pushed into the unplastification area of the plastic material, and in the fourth step, the pushed filter material is held at the pushing position until a strong bond between it and the plastic material is formed. In a method for forming a strong, airtight bond between the plastifyable plate-shaped plastic material for making fluid percolate and the end fringe parts, which are arranged in parallel to each other, of the flat filter material which can not be plastified especially and is folded zigzag, the heat source is composed as an infrared heater having the maximum radiation in a wavelength range of 0.75-1.5 m and energy per unit area of at least 200 kw/m2 .
机译:要解决的问题:与传统方法相比,产生一个合理的滤波器。解决方案:第一步,通过安装在距塑化区域短距离处的热源,在塑料的一部分深度上进行塑化,第二步,移除热源,第三步,结束将过滤材料的边缘部分推入塑料的未塑化区域,然后在第四步中,将推入的过滤材料保持在推入位置,直到在其与塑料之间形成牢固的结合为止。在用于使流体渗透的可塑板状塑料材料和彼此平行布置的端部边缘部分之间形成牢固,气密的结合的扁平过滤材料,该扁平过滤材料尤其不能塑化,并且该热源是折叠的锯齿形,由红外加热器组成,该红外加热器在0.75-1.5 m的波长范围内具有最大辐射,并且每单位面积的能量至少为200 kw / m 2。

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