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The catalytic converter for synthesis gas production and production manner null by methanol resolution of the synthetic gas which uses

机译:用于合成气生产的催化转化器和生产方式由于甲醇分解所使用的合成气无效

摘要

PROBLEM TO BE SOLVED: To efficiently manufacture a synthetic gas by securing a catalyst for generating the synthetic gas at a high selectivity in a decomposing reaction of methanol by a method wherein a catalyst comprises a composite metallic oxide containing cerium, palladium and zirconium, and the palladium is allowed to exist as palladium oxide or the like. ;SOLUTION: A catalyst for manufacture of a synthetic gas is composed of a hydrogen treated material of a composite metallic oxide containing cerium, palladium and zirconium represented by the formula: Ce1-x-yPdxZryO2-x.mH2O (in the formula, (x) represents a number of 0.05-0.7, (y) represents a number of 0.05-0.8, x+y represents a number of under 1 and (m) represents a number of 0-10). At that time the palladium is allowed to exist as a palladium oxide or a metallic palladium. Then, the catalyst is used in a method for manufacture of a synthetic gas by a decomposing reaction of methanol. Thereby, the methanol can be decomposed into the synthetic gas (CO+H2) at a low reaction temperature and at a high selectivity.;COPYRIGHT: (C)2000,JPO
机译:解决的问题:通过在催化剂的甲醇分解反应中包含铈,钯和锆的复合金属氧化物与甲醇的混合反应中,确保用于高选择性地生成合成气的催化剂,从而有效地制造合成气。钯可以作为氧化钯等存在。 ;解决方案:用于制造合成气的催化剂由含铈,钯和锆的复合金属氧化物的氢处理材料组成,该材料由下式表示:Ce1-x-yPdxZryO2-x.mH2O(在公式中,(x )表示0.05-0.7的数字,(y)表示0.05-0.8的数字,x + y表示小于1的数字,(m)表示0-10的数字。那时,允许钯以氧化钯或金属钯的形式存在。然后,将催化剂用于通过甲醇的分解反应制造合成气的方法中。因此,甲醇可以在低反应温度和高选择性下分解为合成气(CO + H2)。版权所有:(C)2000,JPO

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