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Self evaluation power measuring method, the self evaluation power measurement equipment, in the computer network where the self evaluation power

机译:自评估功率测量方法,自评估功率测量设备,在计算机网络中自评估功率所在

摘要

PROBLEM TO BE SOLVED: To improve self-evaluating ability and to raise the self-learning ability by accurately and objectively measuring the self-evaluating ability of a learner.;SOLUTION: As for the learning result of the learner, a 1st difference as a difference between the self-evaluation points by the learner himself and evaluation points by another learner and a 2nd difference as a difference the self-evaluation points and evaluation points by an instructor are calculated based upon evaluation results that the learner himself, instructor, and other learner, and a 3rd difference as a difference between the mean of self-evaluation points of respective learning results in a group of learners and evaluation points by other learners and a 4th difference as a difference between the mean of self-evaluation points of respective learning results in the group of learners and evaluation points by the instructor are calculated; and the absolute values of the difference between the 1st difference and 3rd difference are compared with each other and the absolute values of the 2nd difference and 4th difference are compared with each other to evaluate and output the self-evaluation ability level of the learner as self-evaluation ability points.;COPYRIGHT: (C)2005,JPO&NCIPI
机译:要解决的问题:通过准确客观地衡量学习者的自我评价能力,提高自我评价能力并提高自我学习能力;解决方案:关于学习者的学习成果,第一点区别是学习者本人的自我评价点与另一个学习者的评价点之间的差,以及基于学习者本人,指导者等的评价结果​​,计算作为教员的自我评价点和评价点的差的第二差。学习者,一组学习者的自我评价点的平均值与其他学习者的评价点之差的第3差异,以及各学习者的自我评价点的平均值之间的差之4计算学习者组中的结果和指导者的评估点;并且将第一差和第三差之间的差的绝对值彼此比较,并且将第二差和第四差之间的绝对值彼此比较,以评估并输出学习者的自我评价能力水平作为自我。评估能力点。;版权所有:(C)2005,JPO&NCIPI

著录项

  • 公开/公告号JP3668491B2

    专利类型

  • 公开/公告日2005-07-06

    原文格式PDF

  • 申请/专利权人 里吉 真理子;

    申请/专利号JP20040325737

  • 发明设计人 里吉 竜一;

    申请日2004-11-09

  • 分类号G09B19/00;

  • 国家 JP

  • 入库时间 2022-08-21 22:27:02

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