首页> 外国专利> METHOD FOR NOTIFYING A CALLING SUBSCRIBER THAT A CALLED SUBSCRIBER IS NOT IN A BUSY STATE, ESPECIALLY CONCERNED WITH TRANSMITTING A NOTIFICATION TO A CALLING SUBSCRIBER WHEN A CALLED SUBSCRIBER GETS TO AN ACTIVE STATE

METHOD FOR NOTIFYING A CALLING SUBSCRIBER THAT A CALLED SUBSCRIBER IS NOT IN A BUSY STATE, ESPECIALLY CONCERNED WITH TRANSMITTING A NOTIFICATION TO A CALLING SUBSCRIBER WHEN A CALLED SUBSCRIBER GETS TO AN ACTIVE STATE

机译:通知已调用用户不在忙状态的调用用户的方法,尤其是当已调用用户进入活动状态时,将通知发送给正在调用的用户

摘要

PURPOSE: A method for notifying a calling subscriber that a called subscriber is not in a busy state is provided to inform a calling subscriber of a call-available time with a called subscriber when the called subscriber is busy or not in an active state. CONSTITUTION: In case that a calling subscriber calls a called subscriber when the called subscriber is in a busy state or not in an active sate(52,54), a system sends an announcement to the calling subscriber so that he can select whether he wants to be notified when the called subscriber is in an active(56). If it is confirmed that the calling subscriber wants to be notified, the system checks the state of the called subscriber periodically(58). If the called subscriber gets to an available state, the system calls the called subscriber, notifying the calling subscriber that the called subscriber is available(66,68).
机译:目的:提供一种用于通知主叫用户被叫用户不处于忙状态的方法,以在被叫用户忙或不处于活动状态时向主叫用户通知被叫用户的呼叫可用时间。组成:如果在主叫用户处于忙碌状态或不在活动状态时主叫用户呼叫被叫用户,则系统会向主叫用户发送通知,以便他可以选择是否要当被叫用户处于活动状态时将被通知(56)。如果确定要通知主叫用户,则系统会定期检查被叫用户的状态(58)。如果被叫用户进入可用状态,系统将呼叫被叫用户,并通知主叫用户该被叫用户可用(66,68)。

著录项

  • 公开/公告号KR20040100927A

    专利类型

  • 公开/公告日2004-12-02

    原文格式PDF

  • 申请/专利权人 LUCENT TECHNOLOGIES INC.;

    申请/专利号KR20040034399

  • 发明设计人 LASKEN RICHARD D;

    申请日2004-05-14

  • 分类号H04B7/26;

  • 国家 KR

  • 入库时间 2022-08-21 22:06:27

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