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THREE-PHASE double-layer fractional (Q = B + 0,5) winding of an electrical machine (its variants)

机译:电机的三相三相分数阶(Q = B + 0,5)绕组(其变体)

摘要

1. u0442u0440u0435u0445u0444u0430u0437u043du0430u00a0 u0434u0432u0443u0445u0441u043bu043eu0439u043du0430u00a0 u0434u0440u043eu0431u043du0430u00a0 (q = b + 0.5) wire of electric cars u0432u044bu043fu043eu043bu043du00a0u0435u043cu0430u00a0 2u0440 = 4 - u043fu043eu043bu044eu0441u043du043eu0439 at z = 6cq u043fu0430u0437u0430u0445 from 4 u043au0430u0442u0443u0448u0435u0447u043du044bu0445 groups (b + 1) - u043au0430u0442u0443u0448u0435u0447u043du044bu0445 odds, b - u043au0430u0442u0443u0448u0435u0447u043du044bu0445 even with the middle step u043au043eu043du0446u0435u043du0442u0440u0438u0447u0435u0441u043au0438u0445 coils yu043az / 2pc in general, even with = 1, 2, 3,... 2wu043a u0432u0438u0442u043au0430u0445, each groove and rooms (i = 1,... the (b + 1), i = 1,...b control group, u043du0430u0447u0438u043du0430u00a0 with the outside, u043eu0442u043bu0438u0447u0430u044eu0449u0430u00a0u0441u00a0 so that q = 5.5 (b = 5) group (b + 1) = 6 - u043au0430u0442u0443u0448u0435u0447u043du044bu0435 have steps out u0443u043fi = 13 - 2 (i - 1), with the numbers of turns of (1 - x) wk (i = 1, 6 (1) wu043a + (x) (i = 3, and b = 5 - u043au0430u0442u0443u0448u0435u0447u043du044bu0435 - 'u043fi = 12 - 2 (i - 1) (1 + x) wu043a in i = 3, with wu043a remaining coils groups, where z = 33c and cc = 1,5q - 1 = 8 with the value of x = 0.54.;2. u0442u0440u0435u0445u0444u0430u0437u043du0430u00a0 u0434u0432u0443u0445u0441u043bu043eu0439u043du0430u00a0 u0434u0440u043eu0431u043du0430u00a0 (q = b + 0.5) wire of electric cars u0432u044bu043fu043eu043bu043du00a0u0435u043cu0430u00a0 2u0440 = 4 - u043fu043eu043bu044eu0441u043du043eu0439 at z = 6cq u043fu0430u0437u0430u0445 from 4 u043au0430u0442u0443u0448u0435u0447u043du044bu0445 groups (b + 1) - u043au0430u0442u0443u0448u0435u0447u043du044bu0445 odds, b - u043au0430u0442u0443u0448u0435u0447u043du044bu0445 even with the middle step u043au043eu043du0446u0435u043du0442u0440u0438u0447u0435u0441u043au0438u0445 coils u0443u043az / 2u0440u0441 in general, even with = 1, 2, 3,... 2wu043a u0432u0438u0442u043au0430u0445, each groove and rooms (i = 1,... the (b + 1), i = 1,...b control group, u043du0430u0447u0438u043du0430u00a0 with the outside, u043eu0442u043bu0438u0447u0430u044eu0449u0430u00a0u0441u00a0 so that q = 6.5 (b = 6) group (b + 1) = 7 - u043au0430u0442u0443u0448u0435u0447u043du044bu0435 have steps out u0443u043fi = 16 - 2 (i - 1), with the numbers of turns of (1 - x) wu043a (i = 1, 7 (1) wu043a + (x) (i = 4, and b = 6 - u043au0430u0442u0443u0448u0435u0447u043du044bu0435 - y 'u043fi = 3 - 2 (i - 1) (1 + x) wk (i' = 4, with wk remaining coils groups, where z = 39c uk = 1.5q + 1 = 10, with the meaning of x = 0.54.;3. u0442u0440u0435u0445u0444u0430u0437u043du0430u00a0 u0434u0432u0443u0445u0441u043bu043eu0439u043du0430u00a0 u0434u0440u043eu0431u043du0430u00a0 (q = b + 0.5) wire of electric cars u0432u044bu043fu043eu043bu043du00a0u0435u043cu0430u00a0 2u0440 = 4 - u043fu043eu043bu044eu0441u043du043eu0439 at z = 6cq u043fu0430u0437u0430u0445 from 4 u043au0430u0442u0443u0448u0435u0447u043du044bu0445 groups (b + 1) - u043au0430u0442u0443u0448u0435u0447u043du044bu0445 odds, b - u043au0430u0442u0443u0448u0435u0447u043du044bu0445 even with the middle step u043au043eu043du0446u0435u043du0442u0440u0438u0447u0435u0441u043au0438u0445 coils yu043az / 2pc in general, even with = 1, 2, 3,... 2wu043a u0432u0438u0442u043au0430u0445, each groove and rooms (i = 1,... the (b + 1), i = 1,...b control group, u043du0430u0447u0438u043du0430u00a0 with the outside, u043eu0442u043bu0438u0447u0430u044eu0449u0430u00a0u0441u00a0 so that q = 7.5 (b = 7) group (b + 1) = 8 - u043au0430u0442u0443u0448u0435u0447u043du044bu0435 have steps out yu043fi = 18 - 2 (i - 1), with the numbers of turns of (1 - x) wu043a i = 1 / (1 + (x) wu043a (i = a, b = 4, 7 - to u0430u0442u0443u0448u0435u0447u043du044bu0435 - 'u043fi = 17 - 2 (i - 1) (1 + x) wu043a (i' = 4, with wu043a remaining coils groups, where z = 45c, yu043a = 1,5q - 1 = 11 with the value of x = 0.54.
机译:1. u0442 u0440 u0435 u0445 u0444 u0430 u0437 u043d u0430 u0445 u00a0 u0434 u0432 u0443 u0445 u0441 u043b u043e u0439 u043d u043d u0430 u00a0 u0434 u0434 u0440 u0431 u043d u0430 u00a0(q = b + 0.5)电动车线 u0432 u044b u043f u043e u043b u043d u00a0 u0435 u043c u0430 u00a0 2 u0440 = 4- u043f u043e u043b u044e u0441 u043d u043e u0439 at z = 6cq u043f u0430 u0437 u0430 u0445 from 4 u043a u0430 u0442 u0443 u0448 u0435 u0447 u043d u044b u0445组(b + 1)- u043a u0430 u0442 u0443 u0448 u0435 u0447 u043d u044b u0445赔率,b- u043a u0430 u0442 u0443 u0448 u0435 u0435 u0447 u043d u044b u0445即使使用中间台阶 u043a u043e u043d u0446 u0435 u043d u0442 u0440 u0438 u0447 u0435 u0441 u043a u0438 u0445线圈y u043az / 2pc通常,即使= 1, 2,3,... 2w u043a u0432 u0438 u0442 u043a u0430 u0445,每个凹槽和房间(i = 1,... the(b + 1),i = 1,... b控制组, u043d u0430 u0447 u0438 u043d u0430 u00a0与外部, u043e u0442 u043b u0438 u0447 u0430 u044e u04 49 u0430 u00a0 u0441 u00a0,以使q = 5.5(b = 5)组(b + 1)= 6- u043a u0430 u0442 u0443 u0448 u0435 u0447 u043d u044b u0435有步骤 u0443 u043fi = 13-2(i-1),匝数为(1-x)wk(i = 1,6(1)w u043a +(x)(i = 3,b = 5- u043a u0430 u0442 u0443 u0448 u0435 u0447 u043d u044b u0435-' u043fi = 12-2(i-1)(1 + x)w = i043 in i = 3,其中w u043a其余的线圈组,其中z = 33c,cc = 1,5q-1 = 8,x = 0.54。; 2。 u0442 u0440 u0435 u0445 u0444 u0430 u0437 u043d u0430 u0045 u0014a u043d u0430 u00a0(q = b + 0.5)电动汽车线 u0432 u044b u043f u043e u043e u043b u043d u00a0 u0435 u043c u0430 u00a0 2 u0440 = 4- u043f u043e u043b u044e u0441 u043d u043e u0439 at z = 6cq u043f u0430 u0437 u0430 u0445 from 4 u043a u0430 u0442 u0443 u0448 u0435 u0435 u0447 u043d u044b u0445组(b +1)- u043a u0430 u0442 u0443 u0448 u0435 u0447 u043d u044b u0445赔率,b- u043a u0430 u0442 u0443 u0448 u0435 u0447 u0447 u043d u044b u0445中间线圈 u043a u043e u043d u0446 u0435 u043d u0442 u0440 u0438 u0447 u0435 u0441 u043a u0438 u0445线圈 u0443 u043az / 2 u0440 u0441,即使有= 1,2,3,... 2w u043a u0432 u0438 u0442 u043a u0430 u0445,每个凹槽和房间(i = 1,...(b +1),i = 1 ,. ..b控制组, u043d u0430 u0447 u0438 u043d u0430 u00a0与外部, u043e u0442 u043b u0438 u0447 u04 30 u044e u0449 u0430 u00a0 u0441 u00a0,以便q = 6.5(b = 6)组(b + 1)= 7- u043a u0430 u0442 u0443 u0448 u0435 u0447 u043d u044b u0435走出 u0443 u043fi = 16-2(i-1),匝数为(1-x)w u043a(i = 1,7(1)w u043a +(x)( i = 4,b = 6- u043a u0430 u0442 u0443 u0448 u0435 u0447 u043d u044b u0435-y' u043fi = 3-2(i-1)(1 + x)wk( i'= 4,wk个剩余的线圈组,其中z = 39c uk = 1.5q + 1 = 10,x = 0.54。; 3的含义。 u0442 u0440 u0435 u0445 u0444 u0430 u0437 u043d u0430 u0045 u0014a u043d u0430 u00a0(q = b + 0.5)电动车线 u0432 u044b u043f u043e u043e u043b u043d u00a0 u0435 u043c u0430 u00a0 2 u0440 = 4- u043f u043e u043b u044e u0441 u043d u043e u0439 at z = 6cq u043f u0430 u0437 u0430 u0445 from 4 u043a u0430 u0442 u0443 u0448 u0435 u0435 u0447 u043d u044b u0445组(b +1)- u043a u0430 u0442 u0443 u0448 u0435 u0447 u043d u044b u0445赔率,b- u043a u0430 u0442 u0443 u0448 u0435 u0435 u0447 u043d u044d u044b u0445中间步骤 u043a u043e u043d u0446 u0435 u043d u0442 u0440 u0438 u0447 u0435 u0441 u043a u0438 u0445线圈y u043az通常为2个,即使= 1,2, 3,... 2w u043a u0432 u0438 u0442 u043a u0430 u0445,每个凹槽和房间(i = 1,...(b + 1),i = 1,... b对照组, u043d u0430 u0447 u0438 u043d u0430 u00a0与外部, u043e u0442 u043b u0438 u0447 u0430 u044e u0449 u0430 u00a0 u0441 u00a0,以使q = 7.5(b = 7)组(b + 1)= 8- u043a u0430 u0442 u0443 u0448 u0435 u0447 u043d u044b u0435有步骤y u043fi = 18-2(i-1),匝数为(1-x)w u043a i = 1 /(1 +(x)w u043a(i = a,b = 4,7 -到 u0430 u0442 u0443 u0448 u0435 u0447 u043d u044b u0435-' u043fi = 17-2(i-1)(1 + x)w u043a(i'= 4,且w u043a个剩余的线圈组,其中z = 45c,y u043a = 1,5q-1 = 11,x = 0.54。

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