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TiAl ALLOY SUPERIOR IN HIGH-TEMPERATURE CREEP CHARACTERISTICS AND MANUFACTURING METHOD THEREFOR
TiAl ALLOY SUPERIOR IN HIGH-TEMPERATURE CREEP CHARACTERISTICS AND MANUFACTURING METHOD THEREFOR
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机译：TiAl合金在高温蠕变特性中的优势及其制备方法
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摘要
PROBLEM TO BE SOLVED: To provide a TiAl alloy which has superior high-temperature creep characteristics to a conventional one without impairing its toughness and lightweight properties.;SOLUTION: The TiAl alloy has a composition comprising, by mass%, 31 to 34% Al, 0.1 to 0.7% Si, one or more elements of 0.1 to 15.0% Nb, 0.1 to 15.0% Mo, 0.1 to 15.0% W and 0.1 to 15.0% Ta so that the total amount can satisfy Nb+Mo+W+Ta≤15.0%, one or more elements of 0.1 to 3.0% Cr, 0.1 to 3.0% Mn and 0.1 to 3.0% V so that the total amount can satisfy Cr+Mn+V≤3.0%; 0.01 to 0.12% C and the balance Ti with unavoidable impurities, while satisfying the following expressions (1), (2) and (3): expression (1): value A (=0.15(Nb+Mo+W+Ta)+0.05(Cr+Mn+V)+0.95Si-5C)=0.8 to 3.0; expression (2): Al=(33.5-value A)±0.5; and expression (3): value B (=0.5Si+5C)=0.1 to 0.8.;COPYRIGHT: (C)2008,JPO&INPIT
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机译：解决的问题：提供一种在不损害其韧性和轻质性能的情况下具有优于常规合金的高温蠕变特性的TiAl合金;解决方案：TiAl合金的成分按质量百分比计包括31％至34％的Al ，0.1〜0.7％的Si，0.1〜15.0％的Nb，0.1〜15.0％的Mo，0.1〜15.0％的W和0.1〜15.0％的Ta中的一种或多种元素，从而满足Nb + Mo + W + Ta＆le的总量。 15.0％，0.1〜3.0％的Cr，0.1〜3.0％的Mn和0.1〜3.0％的V中的一种或多种，使得总量可以满足Cr + Mn + V＆le; 3.0％。在满足以下表达式（1），（2）和（3）的同时，添加0.01至0.12％的C和余量的Ti不可避免的杂质：表达式（1）：值A（= 0.15（Nb + Mo + W + Ta）+ 0.05（Cr + Mn + V）+ 0.95Si-5C）= 0.8至3.0;表达式（2）：Al ＝（33.5-值A）＆plusmn; 0.5;式（3）：B值（＝ 0.5Si + 5C）＝ 0.1〜0.8
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