首页> 外国专利> HIGHLY CORROSION-RESISTANT AUSTENITIC STAINLESS STEEL, NUCLEAR POWER GENERATION PLANT CONSTRUCTED BY USING THE STAINLESS STEEL, WELD JOINT AND STRUCTURAL MEMBER

HIGHLY CORROSION-RESISTANT AUSTENITIC STAINLESS STEEL, NUCLEAR POWER GENERATION PLANT CONSTRUCTED BY USING THE STAINLESS STEEL, WELD JOINT AND STRUCTURAL MEMBER

机译:用不锈钢,焊接接头和结构构件构成的高耐腐蚀奥氏体不锈钢,核动力发电厂

摘要

PPROBLEM TO BE SOLVED: To maintain the soundness of a structure of a nuclear reactor by inhibiting stress corrosion cracking even when a scar due to surface working remains on the surface when a plant has been manufactured. PSOLUTION: The austenitic stainless steel includes, by mass%, 17 to 20% Cr, 10 to 13% Ni, 0.001 to 0.020% C, 0.1 to 1.0% Si, 0.1 to 2.0% Mn, 0.035% or less P, 0.015% or less S, 0.01 to 3.0% Mo, 0.001 to 0.08% N, 0.01 to 2.5% Cu and the balance Fe with impurities; and has an M value of 590 to 760, which is calculated according to the expression 1: M=462(C+N)+9.2Si+8.1Mn+13.7Cr+29(Ni+Cu)+18.5Mo, and an S value of 24 to 45, which is calculated according to the expression 2: S=32.7+101C-13Si-1.2Mn-0.9Cr+2Ni-5.3Mo+0.1Cu-179N, wherein symbols for elements in the expressions represent mass% of each component. PCOPYRIGHT: (C)2009,JPO&INPIT
机译:

要解决的问题:即使在制造工厂时由于表面加工而留下的疤痕仍然存在,通过抑制应力腐蚀裂纹来保持核反应堆结构的稳固性。

解决方案:奥氏体不锈钢按质量百分比包括17至20%Cr,10至13%Ni,0.001至0.020%C,0.1至1.0%Si,0.1至2.0%Mn,0.035%或更少的P ,0.015%以下的S,0.01%至3.0%的Mo,0.001%至0.08%的N,0.01%至2.5%的Cu以及其余的Fe具有杂质。 M值为590至760,根据表达式1计算得出:M = 462(C + N)+ 9.2Si + 8.1Mn + 13.7Cr + 29(Ni + Cu)+ 18.5Mo,S为值24至45,根据表达式2计算:S = 32.7 + 101C-13Si-1.2Mn-0.9Cr + 2Ni-5.3Mo + 0.1Cu-179N,其中表达式中元素的符号表示每个组件。

版权:(C)2009,日本特许厅&INPIT

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