首页> 外国专利> DCT/Q/IQ/IDCT bypass algorithm in MPEG to AVC/H.264 transcoding

DCT/Q/IQ/IDCT bypass algorithm in MPEG to AVC/H.264 transcoding

机译:MPEG中的DCT / Q / IQ / IDCT旁路算法到AVC / H.264转码

摘要

In one embodiment, a first DCT block of coefficients is received from a transcoding process. The DCT block is of a first size, such as an 8×8 size, and in a first coding standard, such as MPEG-2. A distribution of zero and non-zero coefficients is then determined from the first DCT block. For example, areas where non-zero coefficients are found may be determined. This may simplify a corresponding sum of absolute difference (SAD) calculation. The SAD is then calculated for a second DCT block of a second size, such as a 4×4 size block, in a second coding standard, such as AVC. The SAD is determined from the coefficients in the first DCT block. Accordingly, the SAD is determined without performing an inverse DCT on the 8×8 block and then computing the SAD for a 4×4 block. It is then determined if a bypass of a DCT operation for the 4×4 block can be performed based on the SAD computed. For example, the SAD is compared to a threshold to determine if a bypass can be performed. In one example, if the coefficients for each 4×4 block are determined that they may be quantized to zero, then the DCT operation may be bypassed. Also, quantization, inverse quantization, and inverse DCT steps may also be bypassed.
机译:在一个实施例中,从代码转换过程接收系数的第一DCT块。 DCT块具有第一尺寸,例如8×8尺寸,并且具有第一编码标准,例如MPEG-2。然后从第一DCT块确定零系数和非零系数的分布。例如,可以确定发现非零系数的区域。这可以简化对应的绝对差之和(SAD)计算。然后,在诸如AVC的第二编码标准中,针对第二尺寸的第二DCT块(诸如4×4尺寸的块)计算SAD。根据第一DCT块中的系数确定SAD。因此,确定SAD而不对8×8块执行逆DCT,然后针对4×4块计算SAD。然后,基于所计算的SAD,确定是否可以对4×4块执行DCT操作的旁路。例如,将SAD与阈值进行比较,以确定是否可以执行旁路。在一个示例中,如果确定每个4×4块的系数可以被量化为零,则可以绕过DCT操作。同样,量化,逆量化和逆DCT步骤也可以被绕过。

著录项

  • 公开/公告号US8102913B2

    专利类型

  • 公开/公告日2012-01-24

    原文格式PDF

  • 申请/专利权人 JEONGNAM YOUN;

    申请/专利号US20060644450

  • 发明设计人 JEONGNAM YOUN;

    申请日2006-12-22

  • 分类号H04N7/12;

  • 国家 US

  • 入库时间 2022-08-21 17:26:34

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