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high-strength steel sheet for more than the tensile strength of 980MPa spot welding

机译:高强度钢板的抗拉强度大于980MPa点焊

摘要

PROBLEM TO BE SOLVED: To form a welded joint having a high cross tension strength and small unevenness of strength between respective joints by spot welding of a high strength steel plate having a tensile strength of 980 MPa or more.;SOLUTION: The high strength steel plate for spot welding having a tensile strength of 980 MPa or more includes, by mass, 0.10-0.30% of C, 0.01-2.50% of Si, 0.30-3.00% of Mn, ≤1.50% of Al, ≤0.015% of P, ≤0.010% of S, ≤0.010% of N, and the balance of Fe and inevitable impurities, and has a brittleness Br of ≤0.0055 which is defined by formula (1): Br=Ceqh×([P]+2×[S]+4×[N]), wherein Ceqh=[C]+[Si]/40+[Cr]/20, and [C], [Si], [Cr], [P], [S], and [N] represent, respectively, contents (mass%) of C, Si, Cr, P, S and N.;COPYRIGHT: (C)2012,JPO&INPIT
机译:解决的问题:通过点焊抗拉强度为980 MPa或更高的高强度钢板,形成具有高横向拉伸强度和各个接头之间的强度不均小的焊接接头;解决方案:高强度钢具有980MPa或更高的抗拉强度的点焊用板按质量计包括0.10-0.30%的C,0.01-2.50%的Si,0.30-3.00%的Mn,1.50%的Al,0.015% P,S的0.010%,N的0.010%,Fe和不可避免的杂质的余量,并且脆性Br为0.0055,由式(1)定义:Br = Ce​​qh×([ P] + 2×[S] + 4×[N]),其中Ceqh = [C] + [Si] / 40 + [Cr] / 20,[C],[Si],[Cr],[P ],[S]和[N]分别代表C,Si,Cr,P,S和N的含量(质量%)。版权所有:(C)2012,JPO&INPIT

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