首页> 外国专利> A METHOD FOR THE ACTIVITY OF ALPHA-KAP_-17-11B(4-DIMETHYLAMINO)PHENYL-21-BASE-19-_P-P-P-E-GAMMA a-49-Delta_-E-20-Delta_AND MEDIA-KEY

A METHOD FOR THE ACTIVITY OF ALPHA-KAP_-17-11B(4-DIMETHYLAMINO)PHENYL-21-BASE-19-_P-P-P-E-GAMMA a-49-Delta_-E-20-Delta_AND MEDIA-KEY

机译:ALPHA-KAP_-17-11B(4-二甲基氨基)苯基] -21-BASE-19-_P-P-P-E-GAMMA a-49-Delta_-E-20-Delta_AND MEDIA-KEY的活性的方法

摘要

The present invention relates to a known synthetic method, alpha-kappa-e_-17-11B (4-dimethylamino) phenyl] 21-yl-19-_rho-p-e-y a-49-delta-e_-e_-20-delta_ (later human cdbeta-4124). (1) [1,2-3-alpha_theta_delta__100 million (acid) - __rho-5 (10), 9 (11) - delta_e_-17 - the only type (2). The EU CD beta 4124 belongs to the anti hormone group.The method according to the present invention is as follows: (i) epoxy resins forming double bonds at position 5 (10) [1,2-3-alpha_theta_delta_100 million (acid) - rho-5 (10), 9 (11) - _-17-_. Formula (II); (ii) 5,10 alpha-17-3.3-[1] is obtained by adding the epsilon pi_zeta_formed at the site of oxidation cyanidation.Alpha959595959595959595959595965;lambda_) - 17-hydroxy 5A zeolite959595nd2-alpha9595959595959595959595Grignard reagent The position of hydroxyl groups formed in the Teutsch reaction of CuCl (A. V) methylsilylation is 5 - 11 [4 - (dimethylamino) phenyl] 1 - 3;2-alpha95953;9595959595959595959595963;_ VI) Reaction, 4-(11B) (two methylamino) phenyl] - [1, 2-3 - alpha, theta, alpha, Delta, [1] (5),(trimethylmethylsilsilane-17-bis-(acid) - 5-9-in-17B9595Alpha__.7) 5,(trimethylmethylsilyl-17-bis-(acid) -5-9-in-situ formation of methyl Grignard reagent at-17B____ - kappa alpha_______96 (eight)
机译:本发明涉及一种已知的合成方法,α-κ-e_-17-11B(4-二甲基氨基)苯基] 21-基-19-rho-peya-49-δ-e_-e_-20-δ(后来人类cdbeta-4124)。 (1)[1,2-3-alpha_theta_delta__亿(酸)-__rho-5(10),9(11)-delta_e_-17-唯一的类型(2)。 EU CD beta 4124属于抗激素类。根据本发明的方法如下:(i)在位置5(10)上形成双键的环氧树脂[1,2-3-alpha_theta_delta_100,000,000(酸)- rho-5(10),9(11)-_-17-_。式(II); (ii)通过添加在氧化氰化位点形成的εpi_zeta_获得5,10 alpha-17-3.3- [1]。Alpha959595959595959595959595 965; lambda_)-17 -羟基5A沸石959595 and2-alpha9595959595955959595959595 Grignard试剂CuCl(A. V)甲基硅烷化的Teutsch反应中形成的羟基的位置是5-11 [4-(二甲基氨基)苯基] 1-3; 2-alpha95953; 9595959595959595959595 963; _VI)反应,4-(11B)(两个甲基氨基)苯基]-[1,2-3-α,theta,alpha,Delta,[1](5),(三甲基甲基硅烷- 17-bis-(acid)-5-9-in-17B9595 Alpha __。7)5,(三甲基甲基甲硅烷基17-双-(酸)-5-9-in-在17B____-kappa alpha_______96处原位形成甲基格氏试剂(八)

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