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METHOD OF PREDICTING THE FORMATION OF TOLERANCE AT ALLERGY TO THE CELL MILK PROTEIN IN CHILDREN OF EARLY AGE

机译:预测对幼儿乳细胞蛋白过敏的形成方法

摘要

FIELD: medicine.;SUBSTANCE: method involves the determination of serum sIgG4 concentration, as well as the additional determination of serum sIgE concentration in the protein components of cow milk by indirect immunofluorescence, prior to the appointment of an elimination diet. With the exponents sIgE≤0.7 and sIgG4 3+, sIgE0.7 and sIgG4 3+, a favorable outcome of tolerance formation is 90.1-97.9%, and with a predictive probability of tolerance formation and no response, diagnostic administration of the product can be carried out after 6 months of elimination diet, and for the exponents sIgE≤0.7 and sIgG4 0-2+, sIgE0.7 and sIgG4 0-2+, the favorable outcome of tolerance formation is from 0 to 19.2%, and with a predictive probability of no response, diagnostic injection of the product can be carried out not earlier than 12 months from the beginning of the elimination diet.;EFFECT: use of the proposed method allows to determine the optimal duration of the elimination diet and reduce the risk of exacerbations in the diagnostic administration of the product, which will greatly facilitate the management of patients with food allergies and will allow to determine in a timely manner the possibility of expanding the ration of the child and thereby reduce the costs of diagnostic and therapeutic-prophylactic measures.;3 tbl
机译:领域:药物;方法:该方法包括在确定淘汰饮食之前,通过间接免疫荧光测定血清sIgG4的浓度,以及通过间接免疫荧光法另外测定牛奶中蛋白质sIgE的浓度。在指数sIgE≤0.7和sIgG4 3 +,sIgE> 0.7和sIgG4 3+的情况下,耐受性形成的有利结果为90.1-97.9%,并且具有耐受性形成的预测可能性且无响应,因此可以对该产品进行诊断性给药在消除饮食6个月后进行,对于sIgE≤0.7和sIgG4 0-2 +,sIgE> 0.7和sIgG4 0-2 +的指数,耐受性形成的有利结果为0至19.2%,并且具有预测性没有反应的可能性,可以在消除饮食开始后的12个月内进行产品的诊断性注射。效果:使用所建议的方法可以确定消除饮食的最佳持续时间,并降低患病的风险。产品诊断性给药的恶化,这将极大地促进对食物过敏患者的管理,并允许及时确定扩大儿童配给量的可能性,从而降低儿童的配药成本诊断和治疗预防措施; 3 tbl

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