首页> 外国专利> METHOD FOR ASSESSING THE LEVEL RESISTANCE OF CHILDREN I-II OF THE HEALTH GROUP BY THE ORAL CAVITY MICROBIOTA VIRUS COMPONENT

METHOD FOR ASSESSING THE LEVEL RESISTANCE OF CHILDREN I-II OF THE HEALTH GROUP BY THE ORAL CAVITY MICROBIOTA VIRUS COMPONENT

机译:口腔微生物菌病毒成分评估健康人群I-II级儿童抵抗力的方法

摘要

FIELD: medicine.;SUBSTANCE: invention refers to medicine, namely to microbiology, laboratory diagnostics and paediatrics, and can be used for assessing the level of children's resistance. Mucous-genetic analysis of the oral fluid for the presence of herpes virus DNA: Epstein-Barr virus, cytomegalovirus, herpes simplex 6, herpes simplex virus 1 and type 2. A resistance level is evaluated: in children not having herpes microbiota in the oral cavity, determine the high resistance, medium resistance – in the presence of one herpes virus, low resistance – association of two or more herpes viruses in the oral fluid.;EFFECT: method enables assessing the level of body resistance of children of I-II group of health by evaluating a significant complex of the viral microbiota component of the oral cavity.;1 cl, 3 tbl, 3 ex
机译:领域:药物;发明:发明是指医学,即微生物学,实验室诊断学和儿科学,并且可以用于评估儿童的抗药性水平。口腔液中是否存在疱疹病毒DNA的粘液遗传分析:爱泼斯坦-巴尔病毒,巨细胞病毒,单纯疱疹6型,单纯疱疹病毒1型和2型。评估抗药性水平:在口腔中无微生物群的儿童中腔,确定高抵抗力,中抵抗力–在一种疱疹病毒的存在下,低抵抗力–两种或多种疱疹病毒在口腔液中的结合。;效果:该方法可评估I-II儿童的身体抵抗力水平通过评估口腔中病毒微生物群组成的重要复合物来进行健康分组;; 1 cl,3 tbl,3 ex

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