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首页> 外文期刊>Bulletin of the Korean Chemical Society >A Theoretical Study on the Mechanism of Methylation of N-methylaniline with CO2 and Silyl Hydrides
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A Theoretical Study on the Mechanism of Methylation of N-methylaniline with CO2 and Silyl Hydrides

机译:N-甲基苯胺与CO2和甲硅烷基氢化物甲基化机理的理论研究

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The mechanism of methylation of N-methylaniline with CO2 and the phenylsilane (PhSiH3) was studied using density functional theory (DFT) at the M05-2X(THF, SMD)/6-311++G**//M05-2X/6-31G* level. The calculations show that the three-component reaction takes place from the reduction of CO2 with PhSiH3, forming the formoxysilane (FOS) species. This hydrosilylation step requires the highest activation free energy barrier (41.6 kcal/mol), and thus can be regarded as the rate-determining step (RDS) for the entire reaction. Once the FOS species is formed, its subsequent formylation with the amine to formamide (FA) species and the two successive reductions of the FA species to the desired methylamine (MA) product are easy to proceed. Furthermore, our calculations show that 1,3-diphenyldisiloxan-1-ol (PhSiH2OSiHOHPh) is together formed with the product MA. The Si-H bond activity in PhSiH2OSiHOHPh is higher than that in reactant PhSiH3 and intermediate phenylsilanol (PhSiH2OH). Thus, there exists a product catalysis as the activation free energy barrier for the FOS species formation is lowered to 36.9 kcal/mol when this species is used as a reducing agent.
机译:采用密度泛函理论(DFT)研究了N-甲基苯胺与CO2和苯基硅烷(PhSiH3)在M05-2X(THF, SMD)/6-311++G**//M05-2X/6-31G*水平下的甲基化机理.计算表明,三组分反应是由CO2与PhSiH3还原而发生的,形成甲氧基硅烷(FOS)物种。该氢化硅烷化步骤需要最高的活化自由能势垒(41.6 kcal/mol),因此可以被视为整个反应的速率决定步骤(RDS)。一旦形成 FOS 物质,其随后与胺的甲酰化转化为甲酰胺 (FA) 物质以及 FA 物质的两次连续还原为所需的甲胺 (MA) 产物很容易进行。此外,我们的计算表明,1,3-二苯基二硅氧烷-1-醇(PhSiH2OSiHOHPh)与产物MA一起形成。PhSiH2OSiHOHPh中的Si-H键活性高于反应物PhSiH3和中间体苯基硅醇(PhSiH2OH)。因此,当 FOS 物质用作还原剂时,存在产物催化,因为 FOS 物质形成的活化自由能势垒降低到 36.9 kcal/mol。

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