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One-Sided Selfish Parking

机译:单面自私停车

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摘要

The present paper considers a discrete analog of the parking problem.Let n be an integer. If n > 1, then we randomly locate an interval (t, t + 1) with integer endpoints on a segment 0, n. Thus, the original segment is divided into two: 0, t and t + 1, n, and each of them is further considered separately likewise the original one. The phrase “randomly” in this problem means that t is a uniformly distributed on a set {1, . . . , n ? 1} random variable. The process of location of the intervals finishes when the lengths of all the remaining intervals are less than 2. Define as Xn the total amount of the located intervals. In the present paper, the expectations {Xn} are calculated. The process described above can be interpreted as a parking process of cars with handlebars on the left. Hence, the driver is able to leave his car only if the place on his left is free. This is exactly the case when the driver cannot take the left end place of any free segment. In this case, Xn stands for the amount of the parked cars.
机译:本文考虑了停车问题的离散模拟。设 n 为整数。如果 n > 1,那么我们在线段 [0, n] 上随机找到一个具有整数端点的区间 (t, t + 1)。因此,原始段分为两个:[0, t] 和 [t + 1, n],并且它们中的每一个都与原始段一样单独考虑。本题中的短语“随机”意味着 t 是均匀分布在集合 {1, . . . , n ? 1} 随机变量上。当所有剩余间隔的长度小于 2 时,间隔的定位过程结束。将定位间隔的总量定义为 Xn。在本文中,计算了期望值{Xn}。上述过程可以解释为左侧车把的汽车的停车过程。因此,只有当司机左边的地方有空时,他才能离开他的车。当驾驶员无法占据任何自由路段的左端位置时,情况正是如此。在这种情况下,Xn 代表停放的汽车数量。

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