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Quantifying shortening of the fractured clavicle assuming clavicular symmetry is unreliable

机译:假设锁骨对称性不可靠,量化锁骨骨折的缩短

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Background One of the more commonly used methods of determining the amount of shortening of the fractured clavicle is by comparing the length of the fractured side to the length of contralateral unfractured clavicle. A pre-existing natural asymmetry can make quantification of shortening using this method unreliable. The goal of this study is to assess the side-to-side variation in clavicle length in 100 uninjured, skeletally mature adults.Materials and methods To assess the side-to-side difference in clavicle length the length of both clavicles of 100 patients on thoracic computed tomography (CT) scans were measured. Patients without a history of pre-CT clavicular injury were included. The measurements were allocated into three groups based on the amount of asymmetry ( 5-10 and > 10 mm). Dominant side and sex were analyzed to determine influence on the length of the clavicle.Results In 30 patients (30), an asymmetry of 5 mm or more was found. 2 of the patients had a side-to-side difference of more than 10 mm. The absolute side-to-side length difference (LD) was 3.74 mm (95 CI 3.15^.32;/?<0.001). A significant association between clavicle length and dominant side or sex was found (p< 0.001).Conclusion These results show that by utilizing a treatment algorithm based upon clavicular symmetry has a potential for error and can lead over- or under-treatment of the fractured clavicle. A significant association between clavicle length and dominant side or sex was found (p< 0.001).
机译:背景 确定锁骨骨折缩短量的更常用的方法之一是将骨折侧的长度与对侧未骨折锁骨的长度进行比较。预先存在的自然不对称性可能使使用这种方法对起酥油的量化变得不可靠。本研究的目的是评估 100 名未受伤、骨骼成熟的成年人锁骨长度的左右变化。材料和方法:为了评估锁骨长度的左右差异,测量了 100 例胸部计算机断层扫描 (CT) 患者的双侧锁骨长度。纳入无CT前锁骨损伤史的患者。根据不对称量( 5-10 和 > 10 mm)将测量值分为三组。分析优势侧和性别以确定对锁骨长度的影响。结果 30例患者(30%)发现不对称性5mm以上。2% 的患者左右差异超过 10 mm。绝对侧长差(LD)为3.74 mm(95%CI 3.15^.32;/?<0.001)。发现锁骨长度与优势侧或性别之间存在显着关联(p< 0.001)。结论 利用基于锁骨对称性的治疗算法存在错误的可能性,并可能导致锁骨骨折的过度治疗或治疗不足。发现锁骨长度与优势侧或性别之间存在显着关联(p< 0.001)。

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