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The 6666 Problem

机译:6666问题

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摘要

How many times must a die be thrown to get four consecutive sixes? More generally, and more precisely,Ql. What is the expected number of times we must throw a die to get n consecutive sixes?The answer, rather suggestively for the numerologically inclined, turns out to beAl. The expected number of throws is 6 + 6~2 + 6~3...+6~n.In some well-known dice games players throw several dice at the same time: in craps a pair (brace) of dice is thrown, while in yahtzee, yam and balut, up to five dice are thrown at a time. However, Q1 is not the same as Q2. What is the expected number of times we must throw a set of n dice until in one throw all n turn up six? Here the number of possible outcomes for one throw is 6" (think of n dice all of different colours), and all outcomes are equally likely, so the answer is simply A2. The expected number of throws of a set of n dice is 6~n.
机译:为了连续四个六次必须掷骰子多少次?更一般地说,更准确地说,Q1。我们必须掷骰子才能连续n次获得n的预期次数是多少?答案对数字学的解释是暗示性的,它是Al。预期的投掷次数为6 + 6〜2 + 6〜3 ... + 6〜n。在一些著名的骰子游戏中,玩家同时投掷多个骰子:掷骰子时会掷出一对(大括号)骰子,而在yahtzee,yam和balut中,一次最多掷5个骰子。但是,Q1与Q2不同。我们必须掷出一组n个骰子,直到一次掷出全部n个变成6的预期次数是多少?在这里,一掷的可能结果数为6“(认为n个骰子所有不同的颜色),并且所有结果的可能性均等,因此答案仅为A2。一组n掷骰子的预期数为6 〜n。

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