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首页> 外文期刊>International Journal of Mathematical Education in Science and Technology >Derivation of some formulae in combinatrics by heuristic methods
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Derivation of some formulae in combinatrics by heuristic methods

机译:启发式方法推导组合式中的某些公式

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摘要

Heuristic methods are more effective for students inlearning permutations and combinations in mathematics than passive learning such as rote memorization of formulae. Two examples, n! and (2n-1)C_n, of finding new combinatorial formulae are discussed from a pedagogical standpoint. First, the factorial of n can be expressed as ∑_(k=0)~(n-1)k·k!, which can be found by a heuristic method. This expression is comparable to representations of powers of r using geometrical series. Second, the number of possible combinations with repetition of n drawings from n elements is denoted (2n-1)C_n, which can be calculated from ∑_(k=0)~(n-1)_nC_(k+1n-1)C_k. The relation ∑_(k=0)~(n-1)_nC_(k+1n-1)C_k=(2n-1)C_n can be found by a heuristic method through a corresponding problem on mapping.
机译:启发式方法对于学生学习数学的排列和组合比被动学习(例如死记硬背公式)更有效。两个例子,n!从教学的角度讨论了(2n-1)C_n,寻找新的组合公式。首先,n的阶乘可以表示为∑_(k = 0)〜(n-1)k·k !,可以通过启发式方法求出。该表达式可与使用几何级数的r的幂表示相媲美。第二,表示从n个元素重复n个图形的可能组合的数量为(2n-1)C_n,可以从∑_(k = 0)〜(n-1)_nC_(k + 1n-1)计算得出C_k。通过启发式方法,通过映射上的相应问题,可以找到关系∑_(k = 0)〜(n-1)_nC_(k + 1n-1)C_k =(2n-1)C_n。

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