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Solving x~(2~k +1) + x + a = 0 in F_(2~n) with gcd(n, k) = 1

机译:使用GCD(n,k)= 1的f_(2〜n)中的x〜(2〜k +1)+ x + a = 0

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摘要

Let N-a be the number of solutions to the equation x(2k + l) + x + a = 0 in F-2(n) where gcd(k, n) = 1. In 2004, by Bluher [2] it was known that possible values of N-a are only 0, 1 and 3. In 2008, Helleseth and Kholosha [13] found criteria for N-a = 1 and an explicit expression of the unique solution when gcd(k, n) = 1. In 2010 [14], the extended version of [13], they also got criteria for N-a = 0, 3. In 2014, Bracken, Tan and Tan [5] presented another criterion for N-a = 0 when n is even and gcd(k, n) = 1. This paper completely solves this equation x(2k + l) + x + a = 0 with only the condition gcd(n, k) = 1. We explicitly calculate all possible zeros in F-2(n) of P-a (x). New criteria for which a, N-a is equal to 0, 1 or 3 are by-products of our result. (C) 2019 Elsevier Inc. All rights reserved.
机译:让NA是F-2(n)中的等式x(2k + 1)+ x + a = 0的解决方案的数量,其中GCD(k,n)= 1. 2004年,通过bluher [2]是已知的NA的可能值仅为0,1和3.在2008年,HelleSeth和Kholosha [13]发现Na = 1的标准以及GCD(k,n)= 1时的独特解决方案的明确表达。[14 ],[13]的扩展版本,它们也有Na = 0,3.在2014年,当N是偶数和GCD(k,n)时,Bracken,Tan和Tan [5]呈现了NA = 0的另一个标准= 1。本文完全解决了该等式x(2k + l)+ x + a = 0,只有条件gcd(n,k)= 1.我们明确地计算了PA的F-2(n)中的所有可能的零( X)。 A,N-A等于0,1或3的新标准是我们的结果的副产品。 (c)2019 Elsevier Inc.保留所有权利。

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