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A graphical method for determining the magnitude and phase of the electric field in the neighbourhood of an antenna carrying a known distribution of current

机译:确定载有已知电流分布的天线附近电场强度和相位的图形方法

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The development of the use of short waves and modern beam systems has given rise to a need for a knowledge of the electric field in the immediate neighbourhood of a transmitting aerial. The mathematical calculation of this field is somewhat laborious, and the following paper describes a graphical method of procedure by means of which calculations may be made for any desired arrangement of a transmitting aerial. A simplified form of Hertz's equations is used to give the field at a point on the ground due to a unit doublet at different heights in a vertical antenna two wavelengths long. A curve is drawn connecting the amplitude of the field at the point with the height of the doublet in the antenna. For convenience of integration of this field along the antenna, the amplitude is divided into two components?one in phase with the current in the doublet and the other in quadrature with it. Curves are given showing the variation of these two components of the electric field with height for distances of the point from the base of the aerial of 0.25, 0.5, 0.75 and 1.0 times the wavelength of the current in the doublet. The field at any intermediate distance can be found by interpolation. The unit doublet used in the calculation of these curves is supposed to carry a current of 1 ampere. The field due to any small element of the aerial with another current distribution is equal to that when it carries 1 ampere multiplied by the current in amperes now in the element If the two components of the electric field at the point considered due to unit current are modified in this way for a few discrete points in the antenna, two new curves may be drawn connecting the two components of the electric field due to any element in the antenna and the height of that element. The areas which these two curves make with the axis denoting height give the total electric fields at the point due to the complete antenna, and in phase and in quadrature respectively with the current in it. The magn-nitude of the resultant field is equal to the square root of the sum of the squares of the two components, and its phase is given by the inverse tangent of their ratio. The phase is determined throughout with respect to the current at the base of the antenna. It is then shown that the method may be applied to find the field at points other than those on the radius vector through the base normal to the antenna. In this way the field may be determined at various points in another parallel antenna. The phase of the field is determined by the same method at various distances from different lengths of antenna, and a figure is given which shows that for distances greater than about 0.3A there is a maximum difference of about 5? between the phase ofthe field of a half-wave antenna and that due to the doublet at its base. This small difference explains why certain calculations based on the assumption that an antenna is small compared with the wavelength are approximately true when applied to anten in which this assumption no longer holds. The effect of the earth is next taken into account and it is shown how the same method may be used to find the field at any distance from an antenna when the dielectric constant and the conductivity of the earth are known.
机译:短波和现代波束系统的使用的发展引起了对在发射天线的近邻中的电场的了解的需求。该领域的数学计算有些费力,下面的论文描述了一种图形化的程序方法,通过该方法可以对发射天线的任何所需布置进行计算。由于在两个波长长的垂直天线中,在不同高度的单位倍增峰,赫兹方程的简化形式用于在地面上的某个点给出场。绘制了一条曲线,将点处的场强与天线中双峰的高度相连。为了方便沿天线对该场进行积分,将振幅分为两个分量:一个分量与双峰电流同相,另一个分量与之正交。给出的曲线示出了电场的这两个分量随高度的变化,即该点到天线天线根部的距离是双峰中电流波长的0.25、0.5、0.75和1.0倍。可以通过插值找到任何中间距离处的场。计算这些曲线时使用的单位倍增线应该承载1安培的电流。如果天线的任何小元件具有另一种电流分布,则其磁场等于当它携带1安培的电流乘以该元件中现在以安培为单位的电流时。对于天线中的几个离散点以这种方式进行了修改,由于天线中的任何元素和该元素的高度,可能会绘制两条新的曲线来连接电场的两个分量。这两条曲线的轴线面积代表高度,给出了由于天线完整而在该点处的总电场,并且其中的电流同相和正交。合成场的幅值等于两个分量的平方和的平方根,其相位由其比率的反正切值给出。相位是相对于天线底部的电流确定的。然后示出了该方法可以被应用以通过与天线垂直的基底在除了半径矢量上的那些点之外的其他点处找到场。这样,可以在另一平行天线的各个点处确定场。磁场的相位是通过相同的方法在距天线不同长度的不同距离处确定的,给出了一个图,该图表明,对于距离大于0.3A的距离,最大差约为5Ω。在半波天线的场相位和由于其基波成倍增加而引起的相位之间。这个很小的差异说明了为什么将基于天线与波长相比较小的假设进行某些计算在应用于该假设不再成立的情况下近似为真。接下来考虑到地球的影响,并且示出了当已知地球的介电常数和电导率时如何使用相同的方法在距天线任何距离处找到磁场。

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