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Factoring nonabelian finite groups into two subsets

机译:将非卡英莲有限群分为两个子集

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A group G is said to be factorized into subsets A1, A2, . . . , As ? G if every element g in G can be uniquely represented as g = g1g2 . . . gs, where gi ∈ Ai, i = 1, 2, . . . , s. We consider the following conjecture: for every finite group G and every factorization n = ab of its order, there is a factorization G = AB with |A| = a and |B| = b. We show that a minimal counterexample to this conjecture must be a nonabelian simple group and prove the conjecture for every finite group the nonabelian composition factors of which have orders less than 10 000.
机译:将G组G组被分解成亚群A1,A2。 。 。 , 作为 ?如果G中的每个元素G可以唯一地表示为G = G1G2。 。 。 GS,其中gi∈ai,i = 1,2,。 。 。 ,s。我们考虑以下猜想:对于每个有限组G和其顺序的每一个分解n = ab,有一个分解g = ab | a | = A和| B | = b。我们表明,这种猜想的最小反击必须是非印记简单组,并为每个有限组证明猜想非标记组成因子,其订单不到10 000。

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