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THE 4-COLOR CUBES PUZZLE

机译:4色立方体拼图

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摘要

Starting with a palette of four colors, a 4-color cube is one where each face is colored with exactly one color and each color appears on some face–there are a total of sixtyeight distinct varieties of 4-color cubes. In the 4-Color Cube puzzle, one is given a set of 4-color cubes and tries to arrange a subset into a larger n×n×n 4-color cube. To solve this puzzle, it is sufficient to fill in the large cube’s n-frame, its corners and edges. For each n we determine a minimal value, fr(n), so that given any arbitrary collection of fr(n) 4-color cubes, there is always a subset which can be used to build an n-frame. In particular, we are able to show that for n ≥ 3, fr(n) = 12n ? 16, the smallest possible number. In addition, we describe a set of ten distinct 4-color cubes from which it is possible to build 2 × 2 × 2 frames modeled on all sixty-eight color cube varieties and conclude that this is the smallest size of such a set.
机译:从四种颜色的调色板开始,一个4色立方体是每张脸上都是一个颜色的颜色,每种颜色都出现在某些面上 - 共有三十型不同的4色立方体品种。在4色立方体拼图中,给出了一组4色立方体,并尝试将子集排列成更大的N×N×N 4色立方体。为了解决这个难题,它足以填充大型立方体的n帧,其角落和边缘。对于每个n,我们确定最小值fr(n),从而给定任何任意收集fr(n)4色多维数据集,总是可以用来构建n帧的子集。特别是,我们能够表明n≥3,fr(n)= 12n? 16,最小的数字。此外,我们描述了一组十种不同的4色多维数据集,可以建立在所有六十八个颜色多方面品种上建模的2×2×2帧,并得出结论,这是这种组的最小尺寸。

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