We solve the currently smallest open case in the 1976 problem of Molluzzo on Z/mZ, namely the case m = 4. This amounts to constructing, for all positive integers n congruent to 0 or 7 mod 8, a sequence of integers modulo 4 of length n generating, by Pascal’s rule, a Steinhaus triangle containing 0,1,2,3 with equal multiplicities.
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机译：我们在z / mz上的molluzzo问题上解决了目前最小的开放式案例，即案例m = 4.这适用于构造，对于所有正整数n一致为0或7 mod 8，一系列整数模数4通过Pascal的规则产生长度N，含有0,1,2,3的Steinhaus三角形，具有相等的多个。
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