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Fast Approach to Factorize Odd Integers with Special Divisors

机译:用特殊除数来将奇数整数进行分解的快速方法

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The paper proves that an odd composite integer N can be factorized in O((log2N)4) bit operations if N = pq, the divisor q is of the form 2αu +1 or 2αu-1 with u being an odd integer and α??being a positive integer and the other divisor p satisfies 1 p ≤ 2α+1 or 2α +1 p ≤ 2α+1-1. Theorems and corollaries are proved with detail mathematical reasoning. Algorithm to factorize the odd composite integers is designed and tested in Maple. The results in the paper demonstrate that fast factorization of odd integers is possible with the help of valuated binary tree.
机译:本文证明,如果n = pq,则除数q是形式2α u +1或2α u +1或2α u + 1或2α u +1或2α u +1或2α u +1或2α u +1或2α u-1与你是一个奇数的奇数,奇数复合整数n可以是o((log2n)4)比特操作。U-1整数和α ??是一个正整数,另一个除数p满足1 ≤ 2α +1或2α +1

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