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How bright can the brightest neutrino source be?

机译:最亮的中微子源是多么明亮?

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摘要

After the discovery of extraterrestrial high-energy neutrinos, the next major goal of neutrino telescopes will be identifying astrophysical objects that produce them. The flux of the brightest source F_(max), however, cannot be probed by studying the diffuse neutrino intensity. We aim at constraining F_(max) by adopting a broken power-law flux distribution, a hypothesis supported by observed properties of any generic astrophysical sources. The first estimate of F_(max) comes from the fact that we can only observe one universe and, hence, the expected number of sources above F_(max) cannot be too small compared with one. For abundant source classes such as starburst galaxies, this one-source constraint yields a value of F_(max) that is an order of magnitude lower than the current upper limits from point-source searches. Then we derive upper limits on F_(max) assuming that the angular power spectrum is still consistent with neutrino shot noise. We find that the limits obtained with upgoing muon neutrinos in IceCube can already be quite competitive, especially for rare but bright source populations such as blazars. The limits will improve nearly quadratically with exposure and, therefore, be even more powerful for the next generation of neutrino telescopes.
机译:在发现外星高能量中微子之后,中微子望远镜的下一个主要目标将识别产生它们的天体物理物体。然而,通过研究漫反射中微子强度,不能探讨最亮源F_(MAX)的通量。我们旨在通过采用破碎的功率 - 法助焊剂分布来限制F_(MAX),这是任何通用天体物理源的观察性质的假设。 F_(MAX)的第一次估计来自于我们只能观察一个宇宙,因此,与一个相比,F_(MAX)的预期源数不能太小。对于arburst星系等丰富的源类,该一个源约束产生f_(max)的值,该值是低于点源搜索的当前上限的数量级。然后,假设角度功率谱仍然与Neutrino Shot噪声一致,我们推出了对F_(MAX)的上限。我们发现,在冰箱中的上升丘中微子获得的限制可能已经是相当有竞争力的,特别是对于罕见但明亮的源人口,如布拉加尔。限制将以暴露几乎具有二次逐步改善,因此对于下一代中微子望远镜而言,更强大。

著录项

  • 来源
    《Physical Review D》 |2017年第12期|103003.1-103003.13|共13页
  • 作者单位

    GRAPPA Institute University of Amsterdam 1098 XH Amsterdam The Netherlands;

    GRAPPA Institute University of Amsterdam 1098 XH Amsterdam The Netherlands;

    GRAPPA Institute University of Amsterdam 1098 XH Amsterdam The Netherlands;

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  • 正文语种 eng
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