首页> 外文期刊>Nucleic acids research >Solution structure of human P1?P2 heterodimer provides insights into the role of eukaryotic stalk in recruiting the ribosome-inactivating protein trichosanthin to the ribosome
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Solution structure of human P1?P2 heterodimer provides insights into the role of eukaryotic stalk in recruiting the ribosome-inactivating protein trichosanthin to the ribosome

机译:人类P1?P2异二聚体的溶液结构为真核茎在将核糖体失活蛋白天花粉蛋白募集到核糖体中的作用提供了见解

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Lateral ribosomal stalk is responsible for binding and recruiting translation factors during protein synthesis. The eukaryotic stalk consists of one P0 protein with two copies of P1?P2 heterodimers to form a P0(P1?P2)2 pentameric P-complex. Here, we have solved the structure of full-length P1?P2 by nuclear magnetic resonance spectroscopy. P1 and P2 dimerize via their helical N-terminal domains, whereas the C-terminal tails of P1?P2 are unstructured and can extend up to ~125 ? away from the dimerization domains. 15N relaxation study reveals that the C-terminal tails are flexible, having a much faster internal mobility than the N-terminal domains. Replacement of prokaryotic L10(L7/L12)4/L11 by eukaryotic P0(P1?P2)2/eL12 rendered Escherichia coli ribosome, which is insensitive to trichosanthin (TCS), susceptible to depurination by TCS and the C-terminal tail was found to be responsible for this depurination. Truncation and insertion studies showed that depurination of hybrid ribosome is dependent on the length of the proline-alanine rich hinge region within the C-terminal tail. All together, we propose a model that recruitment of TCS to the sarcin-ricin loop required the flexible C-terminal tail, and the proline-alanine rich hinge region lengthens this C-terminal tail, allowing the tail to sweep around the ribosome to recruit TCS.
机译:核糖体外侧茎负责蛋白质合成过程中结合和募集翻译因子。真核茎由一个P0蛋白和两个拷贝的P1?P2异二聚体组成,形成一个P0(P1?P2) 2 五聚体P-复合物。在这里,我们已经通过核磁共振波谱解决了全长P1→P2的结构。 P1和P2通过其螺旋N末端结构域二聚,而P1?P2的C末端尾巴是无结构的,可以延伸到〜125?远离二聚化域。 15 N弛豫研究表明,C末端的尾部具有柔性,内部迁移率比N末端的域快得多。用真核P0(P1?P2) 2 / eL12取代原核L10(L7 / L12) 4 / L11产生了对天花粉蛋白(TCS)不敏感的大肠杆菌核糖体容易被TCS净化的C1和C末端尾巴是造成这种净化的原因。截短和插入研究表明,杂合核糖体的去纯化取决于C末端尾巴中富含脯氨酸和丙氨酸的铰链区的长度。总之,我们提出了一个模型,将TCS募集到sarcin-ricin环中需要柔性C末端尾巴,脯氨酸-丙氨酸丰富的铰链区延长了C末端尾巴,从而使尾巴围绕核糖体扫掠以募集TCS。

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