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首页> 外文期刊>Maydica >Genetic distance based on SSR and grain yield of inter and intrapopulational maize single cross hybrids.
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Genetic distance based on SSR and grain yield of inter and intrapopulational maize single cross hybrids.

机译:种间和种内玉米单杂交种基于SSR和籽粒产量的遗传距离。

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摘要

The objective of this work was to correlate the genetic distances between the progenitors obtained by microsatellite markers with the grain yield of inter and intrapopulational maize single cross hybrids. Three S0 populations derived from commercial single cross hybrids were used to obtain 163 hybrids (110 interpopulational and 53 intrapopulational). The two best hybrids and two worst hybrids of each the inter- and intrapopulational crosses were selected and their progenitors maintained through self-pollination of the second ear of each S0 plant, genotyped with 47 SSRs. The Modified Roger’s Distance (MRD) between each pair of S1 inbred lines, the number of alleles and the polymorphic information content (PIC) of each primer were estimated. The genetic distances between progenitors were correlated with the grain yield of the inter- and intrapopulational hybrids. The number of obtained alleles was 186, with a mean of 3.96 alleles. The PIC varied from 0.49 to 0.80, with a mean of 0.65. The mean genetic distance between all S1 inbred lines was 0.75, varying from 0.40 to 0.89, indicating the existence of variability between the S1 inbred lines. The correlation between MRD and grain yield was high and significant for the interpopulational crosses (r = 0.84, P ≤ 0.01) and low and not significant (r = 0.18, P ≥ 0.05) for intrapopulational crosses.
机译:这项工作的目的是使微卫星标记获得的祖细胞之间的遗传距离与种间和种内玉米单杂交种的籽粒产量相关联。使用来自商业单交杂种的三个S0种群获得163个杂种(110个种群间和53个种群内)。选择每个种群间和种群内杂交的两个最好的杂种和两个最差的杂种,并通过对每个S0植物的第二只耳朵进行自花传粉来维持它们的祖先,对它们进行基因分型,具有47个SSR。估计每对S1自交系之间的改良Roger's距离(MRD),等位基因数量和每个引物的多态信息含量(PIC)。祖细胞之间的遗传距离与种群间和种群内杂种的籽粒产量相关。获得的等位基因数量为186,平均为3.96个等位基因。 PIC从0.49到0.80不等,平均值为0.65。所有S1自交系之间的平均遗传距离为0.75,从0.40到0.89不等,表明S1自交系之间存在变异。群体间杂交的MRD与籽粒产量之间的相关性高而显着(r = 0.84,P≤0.01),而种群间杂交的MRD与籽粒产量的相关性则不高(r = 0.18,P≥0.05)。

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