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Mutually orthogonal Latin squares based on general linear groups

机译:基于一般线性组的相互正交的拉丁方

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摘要

Given a finite group G, how many squares are possible in a set of mutually orthogonal Latin squares based on C? This is a question that has been answered for a few classes of groups only, and for no nonsoluble group. For a nonsoluble group G, we know that there exists a pair of orthogonal Latin squares based on G. We can improve on this lower bound when G is one of GL(2, q) or SL(2, q), q a power of 2. q ≠ 2, or is obtained from these groups using quotient group constructions. For nonsoluble groups, that is the extent of our knowledge. We will extend these results by deriving new lower bounds for the number of squares in a set of mutually orthogonal Latin squares based on the group GL(n. q), q a power of 2, q ≠ 2.
机译:给定一个有限的组G,基于C的一组相互正交的拉丁方正方形中可以有多少个正方形?这是仅针对少数几类基团的回答,对于非可溶性基团没有回答。对于一个不可溶的基团G,我们知道存在一对基于G的正交拉丁方。当G为GL(2,q)或SL(2,q),qa的幂次方时,我们可以改善这个下界。 2. q≠2,或使用商组构造从这些组中获得。对于不溶基团,这就是我们所了解的范围。我们将基于组GL(n.q),q的幂为2,q≠2,得出一组相互正交的拉丁方格中的平方数的新下限,从而扩展这些结果。

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