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An Explicit, Characteristic-Free, Equivariant Homology Equivalence Between Koszul Complexes

机译:Koszul配合物之间的显式,无特征的等变同性等价

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Let E and G be free modules of rank e and g, respectively, over a commutative noetherian ring R. The identity map on E* G induces the Koszul complex and its dual Let H(m,n,p) be the homology of the top complex at Sym m E* Sym n G p (E* G) and H(m,n,p) the homology of the bottom complex at D m E D n G* p (E G*). It is known that H(m,n,p) H(m′, n′, p′), provided m + m′ = g − 1, n + n′ = e − 1, p + p′ = (e − 1)(g − 1), and 1 − e ≤ m − n ≤ g − 1. In this article, we exhibit a complex and explicit quasi-isomorphisms from to two complexes, as described above, for the appropriate choice of parameters, which give rise to this isomorphism. Our quasi-isomorphisms may be formed over the ring of integers; they can be passed to an arbitrary ring or field by base change. All of our work is equivariant under the action of the group GL(E) × GL(G); that is, everything we do is independent of the choice of basis.Knowledge of the homology of the top complex is equivalent to knowledge of the modules in the resolution of the Segre module Segre(e,g, ℓ), for ℓ = m − n. The modules {Segre (e,g, ℓ)|ℓ  } are a set of representatives of the divisor class group of the determinantal ring defined by the 2 × 2 minors of an e × g matrix of indeterminates. If R is the ring of integers, then the homology H(m,n,p) is not always a free abelian group. In other words, if R is a field, then the dimension of H(m,n,p) depends on the characteristic of R. The module H(m,n,p) is known when R is a field of characteristic zero; however, this module is not yet known over arbitrary fields.The modules in the minimal resolution of the universal ring for finite length modules of projective dimension two are equal to modules of the form H(m,n,p).View full textDownload full textKey WordsChessboard complex, Determinantal ring, Divisor class group, Equivariant quasi-isomorphism, Finite free resolution, Koszul complex, Segre ring, Universal resolution2000 Mathematics Subject Classification13D25, 16E05, 18G35Related var addthis_config = { ui_cobrand: "Taylor & Francis Online", services_compact: "citeulike,netvibes,twitter,technorati,delicious,linkedin,facebook,stumbleupon,digg,google,more", pubid: "ra-4dff56cd6bb1830b" }; Add to shortlist Link Permalink http://dx.doi.org/10.1080/00927870802107140
机译:令E和G分别在交换Noether环R上分别为等级e和g的自由模块。E * G上的恒等图诱导Koszul络合物,其对偶令H(m,n,p)是H的同源性。 Sym m E * Sym n G p (E * G)和H(m,n,p)处的顶部复合物D m ED n G * p (EG *)处的底部复数。已知H(m,n,p)H(mâ€,nâ€,pâ€),假设m + m = m g = 1,n + n = Âeâ1,p + p = =(eâ1)(gâ1)和1âeÂmân ≥g 1.在本文中,我们展示了一个复杂的和明确的准同构,从如上所述到两个复杂,用于适当选择参数,从而引起了这种同构。我们的准同构可能在整数环上形成;它们可以通过基数更改传递到任意环或字段。在GL(E)×GL(G)组的作用下,我们所有的工作都是等变的;也就是说,我们所做的一切都与基础的选择无关。对顶层复合物同源性的了解等同于Segre模块Segre(e,g,â)的解析中模块的知识,对于„„ “Â=mânân。模块{Segre(e,g,?)|â€}是由e×g的2×2个未成年人定义的行列式环的除数组的一组代表。不确定矩阵。如果R是整数环,则同源性H(m,n,p)并不总是自由的阿贝尔群。换句话说,如果R是一个场,则H(m,n,p)的维数取决于R的特性。当R是特征为零的场时,模块H(m,n,p)已知。但是,此模块尚未在任意字段上获知。投影尺寸为2的有限长度模块的通用环最小分辨率模块等于形式H(m,n,p)的模块。 textKeywords棋盘格,行列式环,除数类组,等变准同构,有限自由分辨率,Koszul复数,Segre环,通用分辨率2000数学主题分类13D25、16E05、18G35 “ citeulike,netvibes,twitter,technorati,美味,linkedin,facebook,stumbleupon,digg,google,更多”,发布:“ ra-4dff56cd6bb1830b”};添加到候选列表链接永久链接http://dx.doi.org/10.1080/00927870802107140

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