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Using 2 m Extended Column Tests to assess slope stability

机译:使用2 m扩展柱测试评估边坡稳定性

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Extended Column Tests (ECTs) are used to assess crack initiation and propagation. Previous research shows that tests 90 cm in length may propagate, suggesting instability, while tests 2 m in length may not propagate, suggesting stability, for identical snowpacks. A practical question is: are 90 cm ECTs optimal for assessing stability? To test the added value of 2 m ECTs for stability evaluation, we collected data on 220 ECTs, with 136 side-by-side standard length ECTPs (full propagation indicating instability) followed by 2 m ECTs. We only performed 2 m ECTs after a standard ECT propagated because we assumed 2 m ECTs would not propagate if standard length tests did not. These tests were preceded by an a priori stability assessment. Our results show imbalances for both tests. The ECT had a similar probability of detection (0.88-0.92, POD), i.e. the ability to detect unstable conditions, as in previous studies, but a much lower probability of null events (0.54-0.75, PON), i.e. the ability to detect stable conditions, with variation due to the binary classification of "Fair" stability as stable or unstable. Adding a 2 m test after an ECTP result lowered the POD (0.49-0.58), but substantially raised the PON (0.88-0.98) of the combined tests. The proportion of tests in agreement, i.e. ECTP and 2 m ECTP, increases with decreasing stability. We conclude that an ECTP followed by a 2 m ECTP is a clear red flag, indicating instability. The interpretation of an ECTP followed by a 2 m ECTN/X (no propagation) is not clear. Though this result suggests stability, a high potential for a false stable result means we cannot recommend the 2 m ECT for binary stability assessments. (C) 2015 Elsevier B.V. All rights reserved.
机译:扩展柱测试(ECT)用于评估裂纹的萌生和扩展。先前的研究表明,对于相同的雪堆,长度为90 cm的测试可能会传播,表明不稳定,而长度为2 m的测试可能不会传播,表明稳定性。一个实际的问题是:90 cm ECTs是否最适合评估稳定性?为了测试2 m ECT的增加值以进行稳定性评估,我们收集了220 ECT的数据,其中136个并排标准长度的ECTP(完全传播表示不稳定),随后是2 m ECT。我们仅在传播标准ECT之后执行了2 m ECT,因为我们假设如果不进行标准长度测试,则不会传播2 m ECT。在进行这些测试之前,需要进行先验稳定性评估。我们的结果显示两种测试均不平衡。 ECT具有与以前的研究类似的检测概率(0.88-0.92,POD),即具有检测不稳定条件的能力,但是具有较低的无效事件概率(0.54-0.75,PON),即具有检测无效条件的能力。稳定条件,由于“公平”稳定性的二进制分类(稳定或不稳定)而有所不同。在ECTP结果之后添加2 m测试会降低POD(0.49-0.58),但会大大提高组合测试的PON(0.88-0.98)。一致性测试的比例(即ECTP和2 m ECTP)随着稳定性的降低而增加。我们得出结论,紧随其后的是2 m ECTP的ECTP是明显的红色标记,表明不稳定。对于ECTP的解释是紧随其后的是2 m ECTN / X(无传播)。尽管此结果表明稳定性,但假性稳定结果的可能性很高,这意味着我们不建议将2 m ECT用于二进制稳定性评估。 (C)2015 Elsevier B.V.保留所有权利。

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