首页> 美国卫生研究院文献>Acta Crystallographica Section E: Crystallographic Communications >Bisbis­(diphenyl­phosphino­yl)acetonitrile-κ2 OO′copper(II)
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Bisbis­(diphenyl­phosphino­yl)acetonitrile-κ2 OO′copper(II)

机译:双双(二苯基膦酰基)乙腈-κ2 OO铜(II)

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摘要

The title complex, [Cu(C26H20NO2P2)2], contains a central CuII atom surrounded by two homoleptic bidentate ligands, which form two five-membered chelate rings. The Cu atom binds to four O atoms, resulting in a four-coordinate square-planar complex. The asymmetric unit contains half of the complex, the other half being completed by inversion symmetry. The Cu—O bond lengths have similar distances, viz. 1.9153 (10) Å for the pair opposite (trans) each other and 1.9373 (10) Å for the other (trans) pair. The P—O bond lengths are 1.5250 (11) Å, indicating significant electron delocalization across the O—P—C—P—O atoms in the chelate ring, resulting in a longer P—O bond length when compared to a formal double-bond P=O character (much shorter at approximately 1.47 Å). The two inter­secting O—Cu—O angles are both linear at 180°, whilst the remaining L-shaped O—Cu—O bond angles are 88.26 (5) and 91.74 (5)°. The C—C N fragment is slightly distorted from linearity at 177.44 (19)° and the C N bond length of 1.151 (2) Å indicates predominantly triple-bond character.
机译:标题复合物[Cu(C26H20NO2P2)2]包含一个中心Cu II 原子,该原子被两个均化的双齿配体包围,形成两个五元螯合环。 Cu原子与四个O原子键合,形成四坐标的方形平面络合物。非对称单元包含复数的一半,另一半通过反对称完成。 Cu-O键长度具有相似的距离,即。彼此相对的(反)对为1.9153(10),另一对(反)为1.9373(10)。 P-O键的长度为1.5250(11)Å,表明整个螯合物环中的O-CP-P-O原子上都有明显的电子离域,与正式的双键相比,PO键的长度更长键P = O(在约1.47Å处短得多)。两个相交的O-Cu-O角在180°处均为线性,而其余的L形O-Cu-O键角为88.26°(5)和91.74°(5)°。 C-C N片段在177.44(19)°处的线性略有失真,并且C N键长度为1.151(2)Å表示主要是三键特征。

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