首页> 美国卫生研究院文献>Acta Crystallographica Section C: Crystal Structure Communications >2-(Diphenyl­phosphinoylmeth­yl)pyrrole–2-(diphenyl­phosphinometh­yl)pyrrole (0.43/0.57) and tetra­chlorido­(5-diphenyl­phosphinometh­yl-2H-pyrrole-κ2 NP)titanium(IV)
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2-(Diphenyl­phosphinoylmeth­yl)pyrrole–2-(diphenyl­phosphinometh­yl)pyrrole (0.43/0.57) and tetra­chlorido­(5-diphenyl­phosphinometh­yl-2H-pyrrole-κ2 NP)titanium(IV)

机译:2-(二苯基­膦酰基甲基­基)吡咯–2-(二苯基­膦酰基甲基­基)吡咯(0.43 / 0.57)和四氯化­(5-二苯基­膦酰基甲基-2基-2H-吡咯-κ2 NP)钛(IV)

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摘要

The title phosphine oxide–phosphine, 0.43C17H16NOP·0.57C17H16NP, (I)/(II), was obtained as a 0.861 (6):1.139 (6) cocrystallized mixture. Hydrogen bonding between the two constituents leads to the formation of 2:2 solid-state assemblies. Instead of forming the expected simple N,P-chelated system via loss of the N-bound H atom, reaction of 2-(diphenyl­phosphinometh­yl)pyrrole, (II), with TiCl4 leads to the formation of the title titanium(IV) complex, [TiCl4(C17H16NP)], (IV), containing a rearranged neutral ligand in which the N-bound H atom moves to one of the pyrrole C atoms, giving a partially unsaturated ring.
机译:得到0.861(6):1.139(6)共结晶混合物的标题氧化膦-膦0.43C17H16NOP·0.57C17H16NP(I)/(II)。两种成分之间的氢键导致形成2:2固态组件。 2-(二苯基膦甲基)吡咯(II)与TiCl4的反应不是通过失去与N结合的H原子形成预期的简单N,P螯合系统,而是导致形成标题钛(IV)配合物, [TiCl4(C17H16NP)],(IV),包含重排的中性配体,其中N键合的H原子移动至吡咯C原子之一,从而获得部分不饱和的环。

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