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Advice Complexity of Fine-Grained Job Shop Scheduling

机译:精细植物店安排的建议复杂性

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We study the advice complexity, which is a tool to measure the amount of information necessary to achieve a certain output quality, of a specific online scheduling problem. A great deal of research has been carried out in this field; however, this paper studies the problem in a new setting. We redefine the cost function of the considered job shop scheduling problem. Up to now, the makespan was taken as the cost function. Thus, every algorithm has a cost of at least m and at most 2m and is, as a consequence, at least 2-competitive, where m denotes the number of jobs. Moreover, Hromkovic et al. [8] constructed an algorithm that has a competitive ratio of at most 1 + 1/{the square root of}m. It seems futile to look for better algorithms with respect to this measurement. To allow a more fine-grained analysis, we take the delay of an algorithm as its cost. We prove that with this new cost measure, the best algorithms so far have competitive ratios of {the square root of}m or {the square root of}m/2 while reading about log_2({the square root of}m) advice bits. Then, we describe a deterministic online algorithm with a competitive ratio of at most 0.67{the square root of}m. We use this deterministic algorithm to construct an online algorithm with advice that reads b ≥ 2 log_2(m) + 1 advice bits and has a competitive ratio of at most max{6, {the square root of}(8 log_2 (m)) ~4{the square root of}m/{the square root of}b}.
机译:我们研究了建议复杂性,这是一种衡量特定在线调度问题所需的信息所需信息量的工具。这一领域已经开展了大量研究;但是,本文研究了新设置中的问题。我们重新定义了考虑的作业商店调度问题的成本函数。到目前为止,Makespan被视为成本职能。因此,每种算法的成本至少为m,并且最多为2m,并且因此至少为2竞争,其中m表示作业的数量。此外,HROMKOVIC等人。 [8]构造了一种竞争比率最多为1 + 1 / {M的平方根。在此测量上寻找更好的算法似乎徒劳。为了允许更细粒度的分析,我们将算法延迟为其成本。我们证明,通过这种新的成本措施,到目前为止的最佳算法具有{M / 2的平方根的平方根的竞争比例,同时读取关于log_2的{m / 2的平方根,{m)建议位。然后,我们描述了一个竞争比例的确定性在线算法,最多为0.67 {m的平方根。我们使用这种确定性算法通过读取B≥2log_2(m)+ 1建议位的建议来构造在线算法,并且具有最多最大{6,{}的平方根}的竞争比率(8 log_2(m)) 〜4 {平方根} m / {b的平方根}。

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