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Secrecy Capacity of a Gaussian Wiretap Channel with One-bit ADCs is Always Positive

机译:具有一位ADC的高斯窃听通道的保密容量始终为正

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We consider the Gaussian wiretap channel with onebit analog-to-digital converters (ADCs) at both the legitimate receiver and the eavesdropper. In this channel, we show that a positive secrecy rate is always achievable whenever the noise power n12 at the legitimate receiver is not the same as the noise power n22 at the eavesdropper. A binary phase-shift keying (BPSK) and an asymmetric BPSK are shown to achieve a positive secrecy rate for the cases of n1 <; n2 and n1 > n2, respectively. We partially justify the choice of these signalings by showing that the optimal input distribution that achieves Rs* := supPX:E[X2]≤P I(X; Y1) - I(X; Y2), where X is the channel input with power constraint of P, and Y1 and Y2 are the channel outputs at the legitimate receiver and the eavesdropper, respectively, should satisfy some symmetric and asymmetric properties for the cases of n1 <; n2 and n1 > n2, respectively. Moreover, for n1 <; n2 and sufficiently large P, it is shown that a BPSK using power smaller than P achieves Rs*.
机译:我们考虑在合法接收器和窃听者端均使用带一位模拟/数字转换器(ADC)的高斯窃听通道。在此通道中,我们表明,只要噪声功率n 1 2 合法接收者处的噪声功率与噪声功率n不相同 2 2 在窃听者。对于n的情况,显示了二进制相移键控(BPSK)和非对称BPSK可以实现正的保密率。 1 <; ñ 2 和n 1 > n 2 , 分别。我们通过证明达到R的最佳输入分布来部分证明对这些信令的选择是合理的 s *:=最高 PX:E [X2]≤ P I(X; Y 1 )-I(X; Y 2 ),其中X是功率限制为P的通道输入,Y 1 和Y 2 在n的情况下,分别是合法接收者和窃听者的通道输出应满足一些对称和非对称特性 1 <; ñ 2 和n 1 > n 2 , 分别。而且,对于n 1 <; ñ 2 和足够大的P,表明使用功率小于P的BPSK可以达到R s *。

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