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On Körner-Marton's sum modulo two problem

机译:关于科尔纳-马顿的模二和问题

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In this paper we study the sum modulo two problem proposed by Körner and Marton. In this source coding problem, two transmitters who observe binary sources X and Y, send messages of limited rate to a receiver whose goal is to compute the sum modulo of X and Y. This problem has been solved for the two special cases of independent and symmetric sources. In both of these cases, the rate pair (H(X|Y), H(Y|X)) is achievable. The best known outer bound for this problem is a conventional cut-set bound, and the best known inner bound is derived by Ahlswede and Han using a combination of Slepian-Wolf and Körner-Marton's coding schemes. In this paper, we propose a new outer bound which is strictly better than the cut-set bound. In particular, we show that the rate pair (H(X|Y), H(Y|X)) is not achievable for any binary sources other than independent and symmetric sources. Then, we study the minimum achievable sum-rate using Ahlswede-Han's region and propose a conjecture that this amount is not less than minimum of Slepian-Wolf and Körner-Marton's achievable sum-rates. We provide some evidences for this conjecture.
机译:在本文中,我们研究了Körner和Marton提出的两个问题。在该源编码问题中,两个发射器遵守二进制源x和y,向接收器发送有限速率的消息,其目标是计算x和y的总和模数。这个问题已经解决了两个独立的特殊情况和对称源。在这两种情况下,可以实现速率对(H(x |),h(y | x))。这个问题的最着名的外部界限是传统的切割绑定,最佳已知的内部界限由Ahlswede和汉族使用斜切 - 狼和马顿的编码方案来源。在本文中,我们提出了一种新的外界,这是比切割绑定的更好。特别是,我们表明,除了独立和对称源之外的任何二进制源,不能可实现率对(H(x |),h(y | x))。然后,我们研究了使用Ahlswede-Han的地区的最低可实现的和率,并提出了猜想这一金额不低于睡眠 - 狼和Körner-Marton可实现的总和率。我们为此猜想提供了一些证据。

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