首页> 外文会议>ASME pressure vessels and piping conference;PVP2008 >FLUID PRESSURE ON RECTANGULAR TANK CONSISTING OF RIGID SIDE WALLS AND RECTILINEARLY DEFORMING BOTTOM PLATE DUE TO UPLIFT MOTION
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FLUID PRESSURE ON RECTANGULAR TANK CONSISTING OF RIGID SIDE WALLS AND RECTILINEARLY DEFORMING BOTTOM PLATE DUE TO UPLIFT MOTION

机译:刚性侧墙矩形壁上的流体压力以及由于上升运动而使底部板呈直线形变形的压力

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Although the uplift motion of flat bottom cylindrical shell tanks has been considered to contribute toward various damage to tanks, the mechanics were not fully understood. As well as computing uplift displacement of the tanks, accurate prediction of fluid pressure accompanied with uplift motion is indispensable to prevent the tanks from severe damage. This paper mathematically derives the fluid pressure on a rectangular tank with unit depth consisting of rigid walls and rectilinearly deforming bottom plate accompanied with the uplift motion. Assuming perfect fluid and velocity potential, the continuity equation is given by Laplace equation. The fluid velocity imparted by motion of rigid walls, immobile bottom plate and rectilinearly deformed bottom plate of tank accompanied with uplift of the tank constitutes boundary conditions. Since this problem is set as the parabolic partial differential equation of Neumann problem, the velocity potential is solved with Fourier-cosine expansion. Derivatives of the velocity potential with respect to time give the fluid pressure at arbitrary point inside the tank. The proposed mathematical solution well converges with a first few terms of Fourier series. Diagrams that depict the fluid pressure normalized by product of angular acceleration and diagonals of the tank are presented.
机译:尽管平底圆柱形壳式储罐的上升运动被认为会对储罐造成各种损坏,但其机理尚不完全清楚。除了计算罐的上扬位移之外,准确预测流体压力和上扬运动也是必不可少的,以防止罐受到严重损坏。本文从数学上推导了矩形水箱上的流体压力,该水箱的单位深度由刚性壁和伴随着上升运动而线性变形的底板组成。假设流体和速度势均理想,则连续性方程式由拉普拉斯方程式给出。由刚性壁的运动,固定的底板和直线变形的底板的运动所产生的流体速度,伴随着底板的抬升,构成了边界条件。由于将此问题设置为Neumann问题的抛物型偏微分方程,因此可以通过傅立叶-余弦展开来求解速度势。速度势随时间的导数给出了油箱内任意位置的流体压力。所提出的数学解很好地与傅立叶级数的前几个项收敛。给出了描绘通过角加速度和油箱对角线的乘积归一化的流体压力的图。

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