It is well known that crystals of NaCl structural type take {100}<011> (cube) slip and{110} (dodecahedron) slip. There are many studies on crystal rotation of NaCl, LiF, MgO, etc. which have made clear roles of the both slips and final orientations in compression or extrusion. Additively it is also reported that crystal rotation of NaCl is mainly caused by {100}<011> slip as shown in elaborate experiments and partly through consideration that each of large sum of polarizability and large radius ratio above 0.63 between cation and anion tends to cause {100}<011 > slip. Another study showed that {111} orientation has maximum dislocation density which causes maximum hardenability in uni-axial deformation of NaCl structure. This study tries to explain how {100} <011 > slip and {110} slip cause crystal rotation and form deformation texture of NaCl structure based on the minimum total slip amount theory by Taylor. In NaCl structure, crystal rotation is theoretically caused solely by {100}<011> slip and not caused by {110}<110> slip. The first hypothesis, however, takes the minimum total slip amount for sum of {100}<011> and {110} slips while the second hypothesis considers only slip of {100}<011>. In bi-axial stretch press forming, the former takes {100}<0hk> as final stable orientation, while the latter shows a rather diverged orientation. In uni-axial compression, final stable orientation shows {111} and {100} in the former, while it shows {111} in the latter. In the former, there happens to be correlation that distribution of the minimum total amount of slip by Taylor factor is rather in inverse proportion to that of percentage of {110}<110> slip in sum of both slips.
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