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L-Models and R-Models for Lambek Calculus Enriched with Additives and the Multiplicative Unit

机译:包含添加剂和乘法单元的Lambek演算的L模型和R模型

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Language and relational models, or L-models and R-models, are two natural classes of models for the Lambek calculus. Completeness w.r.t. L-models was proved by Pentus and completeness w.r.t. R-models by Andreka and Mikulas. It is well known that adding both additive conjunction and disjunction together yields incompleteness, because of the distributive law. The product-free Lambek calculus enriched with conjunction only, however, is complete w.r.t. L-models (Buszkowski) as well as R-models (Andreka and Mikulas). The situation with disjunction turns out to be the opposite: we prove that the product-free Lambek calculus enriched with disjunction only is incomplete w.r.t. L-models as well as R-models. If the empty premises are allowed, the product-free Lambek calculus enriched with conjunction only is still complete w.r.t. L-models but in which the empty word is allowed. Both versions are decidable (PSPACE-complete in fact). Adding the multiplicative unit to represent explicitly the empty word within the L-model paradigm changes the situation in a completely unexpected way. Namely, we prove undecidability for any L-sound extension of the Lambek calculus with conjunction and with the unit, whenever this extension includes certain L-sound rules for the multiplicative unit, to express the natural algebraic properties of the empty word. Moreover, we obtain undecidability for a small fragment with only one implication, conjunction, and the unit, obeying these natural rules. This proof proceeds by the encoding of two-counter Minsky machines.
机译:语言和关系模型,或L模型和R模型,是Lambek演算的两个自然类模型。完整性L模型由Pentus和完整性w.r.t. R模型由Andreka和Mikulas撰写。众所周知,由于分布定律,将加法连接和分离相加在一起会导致不完整。但是,仅乘积不加乘积的无乘积Lambek演算是完整的。 L模型(Buszkowski)以及R模型(Andreka和Mikulas)。析取的情况恰恰相反:我们证明仅富集析取的无乘积Lambek演算是不完整的。 L模型以及R模型。如果允许使用空的前提,则仅加乘积的无乘积Lambek演算仍然完整。 L模型,但其中允许使用空词。两种版本均可确定(实际上是PSPACE完整的)。添加乘法单元以明确表示L模型范例中的空词会完全改变情况。也就是说,只要Lambek微积分的任何L声扩展与连词和与该单元的L声扩展有关,只要该扩展包括用于乘法单元的某些L声规则,就可以表达该空词的自然代数性质,则我们无法确定。而且,我们服从这些自然法则,对于只有一个蕴涵,连词和单位的小片段,具有不确定性。通过对两台Minsky机器进行编码来证明这一点。

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