【24h】

Broadcast in Radio Networks Tolerating Byzantine Adversarial Behavior

机译:广播网络中的广播,容忍拜占庭的对抗行为

获取原文
获取原文并翻译 | 示例

摘要

Much work has focused on the Byzantine Generals (or secure broadcast) problem in the standard model in which pairwise communication is available between all parties in the network. Some research has also explored the problem when pairwise channels exist only between selected pairs of players, or under the assumption of "k-cast channels" shared by all subsets of players of size k. However, none of these models are appropriate for radio networks in which a player can communicate only by multicasting a message which is then received by all players within some radius r (i.e., the neighbors of the transmitting node). Yet, as far as we are aware, obtaining secure broadcast in radio networks in the presence of a Byzantine adversary has not been studied before. This paper corrects this omission, and provides the first analysis of secure broadcast in radio networks for the case of Byzantine adversaries. We note that secure broadcast is impossible in the presence of an omnipotent adversary. To bypass this barrier, we make the following assumption: there exists a prefixed schedule for players to communicate and everyone (including corrupted ones) adheres to this schedule. Under this assumption, we give a simple broadcast protocol which is provably secure whenever the adversary corrupts at most 1/4r(r + (r/2)~(1/2)+ 1) — 3 neighbors (roughly a 1/4π fraction) of any honest player. On the other hand, we show that it is impossible to achieve secure broadcast when the adversary corrupts [1/2r(2r + 1)] (roughly a 1/π fraction) neighbors of any honest player.
机译:许多工作集中在标准模型中的拜占庭将军(或安全广播)问题上,在该模型中,网络中所有各方之间都可以使用成对通信。一些研究还探讨了当成对频道仅存在于选定的成对玩家之间时,或在大小为k的所有玩家子集共享“ k播送频道”的假设下的问题。然而,这些模型都不适合于其中播放器只能通过多播消息来进行通信的无线电网络,该消息然后被某个半径r内的所有播放器(即,发送节点的邻居)接收。然而,据我们所知,以前没有研究过在拜占庭对手在场的情况下在无线电网络中获得安全广播。本文纠正了这一遗漏,并针对拜占庭对手的情况,对无线电网络中的安全广播进行了首次分析。我们注意到,在无所不能的对手面前,安全广播是不可能的。为了绕过此障碍,我们做出以下假设:存在一个供玩家进行交流的预定时间表,每个人(包括腐败的玩家)都遵守该时间表。在此假设下,我们给出了一个简单的广播协议,只要对手破坏最多1 / 4r(r +(r / 2)〜(1/2)+1)-3个邻居(大约1 /4π分数),就可以证明它是安全的)的任何诚实玩家。另一方面,我们表明,当对手破坏任何诚实玩家的[1 / 2r(2r + 1)](大约为1 /π分数)时,就不可能实现安全广播。

著录项

相似文献

  • 外文文献
  • 中文文献
  • 专利
获取原文

客服邮箱:kefu@zhangqiaokeyan.com

京公网安备:11010802029741号 ICP备案号:京ICP备15016152号-6 六维联合信息科技 (北京) 有限公司©版权所有
  • 客服微信

  • 服务号