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首页> 外文期刊>Angewandte Chemie >How Does a Coordinated Radical Ligand Affect the Spin Crossover Properties in an Octahedral Iron(II) Complex?
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How Does a Coordinated Radical Ligand Affect the Spin Crossover Properties in an Octahedral Iron(II) Complex?

机译:配位自由基配体如何影响八面体铁(II)配合物的自旋交叉性质?

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The influence of a coordinated π-radical on the spin crossover properties of an octahedral iron(II) complex was investigated by preparing and isolating the iron(II) complex containing the tetradentate N,N'-dimethyl-2,11-diaza[3.3]-(2,6)pyridinophane and the radical anion of N,N'-diphenyl-acenaphtene-1,2-diimine as ligands. This spin crossover complex was obtained by a reduction of the corresponding low-spin iron(II) complex with the neutral diimine ligand, demonstrating that the reduction of the strong n-acceptor ligand is accompanied by a decrease in the ligand field strength. Characterization of the iron(II) radical complex by structural, magnetochemical, and spectroscopic methods revealed that spin crossover equilibrium occurs above 240 K between an S = 1/2 ground state and an S = 3/2 excited spin state. The possible origins of the fast spin interconversion observed for this complex are discussed.
机译:通过制备和分离含有四齿N,N'-二甲基-2,11-二氮杂[III]的铁(II)络合物,研究了配位π自由基对八面体铁(II)络合物的自旋交联性能的影响。 ]-(2,6)吡啶oph烷和N,N'-二苯--1,2-二亚胺的自由基阴离子作为配体。该自旋交叉络合物是通过用中性二亚胺配体还原相应的低自旋铁(II)配合物而获得的,表明强的n-受体配体的还原伴随着配体场强的降低。通过结构,磁化学和光谱学方法对铁(II)自由基络合物的表征表明,自旋交叉平衡发生在240 K以上的S = 1/2基态和S = 3/2激发自旋态之间。讨论了对该复合物观察到的快速自旋互变的可能起源。

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