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首页> 外文期刊>Plasmid: An International Journal Devoted to Extrachromosomal Gene Systems >Instability of pUC19 in Escherichia coli transcription termination factor mutant, rho026.
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Instability of pUC19 in Escherichia coli transcription termination factor mutant, rho026.

机译:pUC19在大肠杆菌转录终止因子突变体rho026中的不稳定性。

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摘要

The higher copy number of pUC19, compared to its parent plasmid pBR322, is known to be due to deletion of rop, also known as rom, and to an ori mutation that impedes RNAI:RNAII interaction. pUC19, unlike pBR322, fails to transform E. coli rho mutant rho026 cells. Here we identify two features of pUC19 that contribute to this transformation defect. (1) The pUCori mutation is involved because replacing the pUCori with that of pBR322 restored transformation. (2) Transcription from the lac promoter in pUC19 is important, since deletion or inversion of the promoter or insertion of a transcription terminator (lambdat0) downstream of it restored transformation. Host RNase E activity is responsible for the transformation defect because introduction of an rne-1 allele into rho026 cells suppressed this defect, indicating that RNAI instability due to RNase E is aggravated in the rho026 strain. We suggest that in rho026 cells pUC19 RNAI:RNAII interaction is more impeded than in rho+ cells and Rop/Rom may confer stability by protecting RNAI against RNase E activity because expression of a rom gene inserted into pUC19 restored transformation. Copyright 1999 Academic Press.
机译:与它的亲本质粒pBR322相比,pUC19的拷贝数较高,这是由于rop的缺失(也称为rom)以及阻碍RNA干扰RNA:RNA相互作用的ori突变引起的。与pBR322不同,pUC19无法转化大肠杆菌rho突变体rho026细胞。在这里,我们确定了导致这种转化缺陷的pUC19的两个特征。 (1)之所以涉及到pUCori突变,是因为用pBR322恢复了pUCori的转化。 (2)从pUC19中的lac启动子的转录是重要的,因为启动子的缺失或倒置或在其下游的转录终止子(lambdat0)的插入恢复了转化。宿主RNase E活性是造成转化缺陷的原因,因为将rne-1等位基因引入rho026细胞可抑制该缺陷,这表明rho026菌株会加剧由于RNase E引起的RNAI不稳定性。我们建议在rho026细胞中,pUC19 RNAI:RNAII的相互作用比在rho +细胞中更受阻碍,并且Rop / Rom可能通过保护RNAI抵抗RNase E活性而赋予稳定性,因为插入rom基因的表达恢复了pUC19的转化。版权所有1999 Academic Press。

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