PROBLEM TO BE SOLVED: To create an electron love + a proton love = a neutron love in a place where nuclear fusion is performed. The neutron love is a proton love (right rotation) + an electron love (left rotation), so why is it left rotation? Since the temperature at the center of the sun where the fusion reaction takes place is 15 x 106 ° C, A = (15 x 106) 1/2 = 3.873 x 103 in this place. So, in the place where nuclear fusion takes place, the attractive force between the electron love and the proton love = attractive force 2 ÷ distance 2 = (3.873 × 103) 2 × (3.873 × 103) 2 = (3.873 × 103) 4 = 2.250 × 1014, double. This is the principle that electron love + proton love = neutron love can be created in the field of nuclear fusion. If work energy = running distance x weight of the runner, then work energy of the electronic love = distance running on the ground surface in one minute x mass of the electronic love = 6.7036 x 105m x 9.109 x 10-31Kg = 6.106 x 10-25mKg .. Work energy of proton love = distance running on the surface of the earth in 1 minute x mass of proton love = 1.992 x 10-1m x 1.673 x 10-27Kg = 3.333 x 10-28mKg [Selection diagram] Fig. 1
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机译:要解决的问题:创造一个电子爱+质子爱=在执行核融合的地方中的中子爱。中子爱是一个质子的爱(右旋)+电子爱情(左旋转),为什么它左转?由于融合反应发生的阳光中心的温度为15×106℃,而在该地方的=(15×10 6)1/2 = 3.873×103。所以,在核融合发生的地方,电子爱与质子的有吸引力和质子爱=有吸引力的力2÷距离2 =(3.873×103)2×(3.873×103)2 =(3.873×103)4 = 2.250×1014,双倍。这是电子爱+质子爱=中子爱情可以在核聚变领域创造的原则。如果工作能量=运行距离x重量的跑步者,那么电子爱的工作能量=距离在地面上运行的距离在一个分钟的x mass的电子爱= 6.19 x 10-31kg = 6.106 x 10- 25mkg .. Proton Love的工作能量=距离在地球表面上的距离在1分钟x大众的proton love = 1.992 x 10-1m x 1.673 x 10-27kg = 3.333 x 10-28mkg [选择图]图1
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