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HYDROGEN STORAGE ALLOY EXCELLENT IN PLATEAU FLATNESS
HYDROGEN STORAGE ALLOY EXCELLENT IN PLATEAU FLATNESS
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机译:高原无氧储氢合金
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摘要
PROBLEM TO BE SOLVED: To provide a hydrogen storage alloy improved in plateau flatness, widen in using environments and furthermore excellent in occluding and releasing characteristics, as to a hydrogen storage alloy excellent in plateau flatness, particularly the one in which a fourth element is added to a Ti-Cr-V series, by forming its metallic structure of the one of the BCC single phase or converting it into the one of BCC single phase by heat treatment. ;SOLUTION: In an alloy expressed by the general formula of Tia Crb Vc Ad with the ratios of numbers of atoms as (a), (b), (c) and (d), where a+b+c+d=100, (A) denotes one or ≥ two kinds among the group IIIb, Mn, Co, Ni, Zr, Nb, Hf, Ta and Al, and, also, compositional regions of 14≤a≤60, 14≤b≤60, 9≤c≤60 and 0d8 or 9≤c≤25 are regulated and having a structure of BCC(body-centered cubic) + C14 (Laves phase), it is heated at 1000 to 1400°C and is rapidly cooled to convert its structure into the one of the BCC single phase.;COPYRIGHT: (C)1999,JPO
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机译:解决的问题:对于高原平坦性优异的储氢合金,特别是其中添加了第四元素的储氢合金,其目的是提供一种平坦度提高,使用环境扩大,吸藏,脱模性优异的储氢合金。通过形成其BCC单相之一的金属结构或通过热处理将其转变为BCC单相之一而制成Ti-Cr-V系列。 ;解决方案:在由Ti a Sub> Cr b Sub> V c Sub> A d Sub>通式表示的合金中原子数之比为(a),(b),(c)和(d),其中a + b + c + d = 100,(A)表示IIIb,Mn,Co组中的一种或两种以上,Ni,Zr,Nb,Hf,Ta和Al以及14≤a≤60、14≤b≤60、9≤c≤60和0 展开▼