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Aluminum alloy null for aluminum wheel casting

机译:铝合金轮毂铸造用铝合金

摘要

PROBLEM TO BE SOLVED: To obtain a high strength and high toughness aluminum alloy member by providing it with a compsn. consisting of the specified ratio of Si, Mn, Sb and Sr in which the ratio of Sb/Sr also is in a specified range and the balance consists substantially of Al. ;SOLUTION: This alloy member has a compsn. contg., by weight, 6.5 to 7.5% Si, 0.2 to 0.4% Mg, ≤0.024% (including no zero) Sb, 0.003 to 0.03% Sr in which the ratio of Sb/Sr is in the range of 0.1 to 0.8 and the balance consists substantially of Al. As for the balance, besides Al, Cu, Fe, Ni, Zn, Ti, Mn, Sn and Ca may be contained but the contents thereof are made to the following ranges. The content of Cu is made to ≤0.2%, that of Fe is made to ≤0.2%, that of Ni is made to ≤0.05%, that of Zn is made to ≤0.10%, that of Ti is made to ≤0.20%, that of Mn is made to ≤0.10%, that of Sn is made to ≤0.05% and that of Ca is made to ≤0.01%. In this way, as the high strength and high toughness aluminum alloy member, e.g. an aluminum wheel is obtd.;COPYRIGHT: (C)1999,JPO
机译:要解决的问题:通过提供复合材料来获得高强度和高韧性的铝合金构件。由指定比例的Si,Mn,Sb和Sr组成,其中Sb / Sr的比例也处于指定范围内,其余部分基本上由Al组成。 ;解决方案:该合金构件具有组件。以重量计,包括6.5至7.5%的Si,0.2至0.4%的Mg,≤0.024%(不包括零)的Sb,0.003至0.03%的Sr,其中Sb / Sr之比在0.1至0.8的范围内并且其余部分基本上由铝组成。关于平衡,除了Al之外,还可以包含Cu,Fe,Ni,Zn,Ti,Mn,Sn和Ca,但是其含量在以下范围内。将Cu的含量设为≤0.2%,将Fe的含量设为≤0.2%,将Ni的含量设为≤0.05%,将Zn的含量设为≤0.10%,将Ti的含量设为≤0.20%。 Mn的含量≤0.10%,Sn的含量≤0.05%,Ca的含量≤0.01%。这样,作为高强度高韧性的铝合金构件,例如版权所有。(C)1999,日本特许厅

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