首页> 外国专利> FERRITIC STAINLESS STEEL SHEET HAVING EXCELLENT CORROSION RESISTANCE IN DISSIMILAR WELD WITH AUSTENITIC STAINLESS STEEL, AND METHOD FOR PRODUCING THE SAME

FERRITIC STAINLESS STEEL SHEET HAVING EXCELLENT CORROSION RESISTANCE IN DISSIMILAR WELD WITH AUSTENITIC STAINLESS STEEL, AND METHOD FOR PRODUCING THE SAME

机译:在奥氏体不锈钢异种焊接中具有优异耐蚀性的铁素体不锈钢板及其制造方法

摘要

PROBLEM TO BE SOLVED: To provide a ferritic stainless steel sheet in which sufficient corrosion resistance can be secured even regarding dissimilar welds with an austenitic stainless steel (e.g., SUS304).;SOLUTION: The ferritic stainless steel sheet has a composition comprising, by mass, ≤0.030% C, ≤0.030% N, ≤0.050% (C+N), ≤0.50% Si, ≤0.50% Mn, ≤0.10% Al, 20.5 to 22.5% Cr, 0.30 to 1.00% Cu, ≤1.50% Ni, 0.20 to 0.70% Nb, ≤0.040% P and ≤0.010% S, and in which these components satisfy the relations in inequality; (Cr+1.5Si+0.5Nb)≤23.0 and inequality; (Ni+30C+0.5Mn+0.5Cu+30N)≥0.90, and the balance Fe with inevitable impurities.;COPYRIGHT: (C)2008,JPO&INPIT
机译:要解决的问题:提供一种即使在与奥氏体不锈钢(例如SUS304)的异种焊缝中也能确保足够耐腐蚀性的铁素体不锈钢薄板;解决方案:铁素体不锈钢薄板的成分组成按质量计,0.03%C,0.030%N,0.050%(C + N),0.50%Si,0.50%Mn,0.10%Al,20.5至22.5%Cr,0.30至1.00 %Cu,≤1.50%Ni,0.20〜0.70%Nb,≤0.040%P和≤0.010%S,并且这些成分满足不等式的关系。 (Cr + 1.5Si + 0.5Nb)≤ 23.0和不等式; (Ni + 30C + 0.5Mn + 0.5Cu + 30N)≥ 0.90,余下的Fe不可避免地带有杂质。;版权所有:(C)2008,日本特许厅

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