首页> 外文OA文献 >NAD(P)H-dependent chromium (VI) reductase of Pseudomonas ambigua G-1: a Cr(V) intermediate is formed during the reduction of Cr(VI) to Cr(III).
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NAD(P)H-dependent chromium (VI) reductase of Pseudomonas ambigua G-1: a Cr(V) intermediate is formed during the reduction of Cr(VI) to Cr(III).

机译:假单胞菌G-1的NAD(P)H依赖型铬(VI)还原酶:在Cr(VI)还原为Cr(III)的过程中形成了Cr(V)中间体。

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摘要

An NAD(P)H-dependent Cr(VI) reductase (molecular weight = 65,000) was purified from a Cr(VI)-resistant bacterium, Pseudomonas ambigua G-1. Stoichiometric analysis of the enzymatic reaction showed that the enzyme catalyzed the reduction of 1 mol of Cr(VI) to Cr(III) while consuming 3 mol of NADH as an electron donor. Chromium(VI) was reduced to Cr(V) by one equivalent NADH molecule in the absence of the enzyme. Electron spin resonance analysis showed that Cr(V) species (g = 1.979) was formed during the enzymatic reduction. The amount of Cr(V) species formed was about 10 times larger than that of the nonezymatic reduction. These findings show that the Cr(VI) reductase reduced Cr(VI) to Cr(III) with at least two reaction steps via Cr(V) as an intermediate.
机译:NAD(P)H依赖的Cr(VI)还原酶(分子量= 65,000)是从耐Cr(VI)的细菌比安普氏假单胞菌G-1中纯化得到的。酶促反应的化学计量分析表明,该酶催化了1 mol Cr(VI)还原为Cr(III),同时消耗了3 mol NADH作为电子供体。在不存在酶的情况下,铬(VI)被一个当量的NADH分子还原为Cr(V)。电子自旋共振分析表明在酶促还原过程中形成了Cr(V)物种(g = 1.979)。形成的Cr(V)种类的量约为非酶还原反应的10倍。这些发现表明Cr(VI)还原酶通过Cr(V)作为中间体,通过至少两个反应步骤将Cr(VI)还原为Cr(III)。

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